M+4n=8
m=n-2
we see that m=n-2
so we can subsitute 'n-2' for m in the first equation
(n-2)+4n=8
n-2+4n=8
5n-2=8
add 2 to both sides
5n=10
divide by 5
n=2
subsitute
n=2
m=n-2
m=2-2
m=0
m=0
n=2
the answer is c. 0,2
Answer:
Step-by-step explanation:
x < -12, so x+12 < 0
| x-(-12) | = | x+12 | = -x-12
Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
A² + b² = c².
Make a triangle with the points on a grid.
One leg is 7 units and the other is 1 unit.
7² is 49 and 1² is 1.
49 + 1 = 50
√50 ≈ 7.071.
Hope this helps!
