Answer:
HNO2
Explanation:
Because H2CO3 is a weak acid in CH3COOH
Answer:
1) When 69.9 g heptane is burned it releases 5.6 mol water.
2) C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.
Explanation:
- Firstly, we should balance the equation of heptane combustion.
- The balanced equation is: <em>C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.</em>
This means that every 1.0 mole of complete combustion of heptane will release 8 moles of H₂O.
- We need to calculate the no. of moles in 69.9 g of heptane that is burned using the relation: <em>n = mass/molar mass.</em>
n of 69.9 g of heptane = mass/molar mass = (69.9 g)/(100.21 g/mol) = 0.697 mol ≅ 0.7 mol.
<em><u>Using cross multiplication:</u></em>
1.0 mol of heptane releases → 8 moles of water.
0.7 mol of heptane releases → ??? moles of water.
<em>∴ The no. of moles of water that will be released from burning (69.9 g) of water</em> = (0.7 mol)(8.0 mol)/(1.0 mol) = <em>5.6 mol.</em>
<em>∴ When 69.9 g heptane is burned it releases </em><em>5.6</em><em> mol water. </em>
<em />
Answer:
125 L of 15% and 265.625 L of 65% HCl
Explanation:
let x = volume of 15% HCl, y = 65% HCl
15x + 65y = 49 × 390.625
15x + 65y = 19140.625
x + y = 390.625
x = 390.625 - y
substitute for x in equation 1
15 (390.625 - y) + 65y = 19140.625
5859.375 - 15 y + 65 y = 19140.625
50 y = 19140.625 - 5859.375 = 13281.25
y = 132181.25 / 50 = 265.625 L
X = 390.625 - y = 390.625 - 265.625 = 125 L
Answer:
The wavelength of this light is 780.4 nm.
Explanation:
Given that,
The frequency of laser light,
We need to find the wavelength of this light.
We know that,
Where
is the wavelength of light
So,
So, the wavelength of this light is 780.4 nm.