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ozzi
3 years ago
8

Will reward brainliest Explain why all arrhenius acids can be considered bronsted lowry acids

Chemistry
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

Explanation:

A bronsted lowry acid just means that it donates a proton.

An arrhenius acid dissolves in water to donate a proton

the only difference is that an arrhenius acid must dissolve in water but it still donates a proton so it is considered a bronsted lowry acid

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Neptunium, Protactinium, plutonium and more

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A lead mass is heated and placed in a foam cup calorimeter containing 50.0 ml of water at 18.0°c. the water reaches a temperatur
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Heat = mC(T2-T1) 

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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is the max
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<u>Answer:</u> The mass of aluminium chloride that can be formed are 46.3 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  ....(1)  

  • <u>For Aluminium:</u>

Given mass of aluminium = 32 g  

Molar mass of aluminium = 26.98 g/mol

Putting values in above equation, we get:  

\text{Moles of aluminium}=\frac{32g}{26.98g/mol}=1.186mol

  • <u>For Chlorine:</u>

Given mass of chlorine = 37 g  

Molar mass of chlorine = 71 g/mol

Putting values in above equation, we get:  

\text{Moles of chlorine gas}=\frac{37g}{71g/mol}=0.521mol

For the given chemical equation:

2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

By Stoichiometry of the reaction:

3 moles of chlorine gas is reacting with 2 moles of aluminium.

So, 0.521 moles of chlorine gas will react with = \frac{2}{3}\times 0.521=0.347moles of aluminium.

As, given amount of aluminium is more than the required amount. Thus, it is considered as an excess reagent.

So, chlorine gas is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

3 moles of chlorine gas is producing 2 moles of aluminium chloride

So,  0.521 moles of chlorine gas will react with = \frac{2}{3}\times 0.521=0.347moles of aluminium chloride.

Now, calculating the mass of aluminium chloride by using equation 1, we get:

Moles of aluminium chloride = 0.347 moles

Molar mass of aluminium chloride = 133.34 g/mol

Putting all the values in equation 1, we get:

0.347mol=\frac{\text{Mass of aluminium chloride}}{133.34g/mol}\\\\\text{Mass of aluminium chloride}=46.3g

Hence, the mass of aluminium chloride that can be formed are 46.3 g

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