A school typically sells 500 yearbooks . . .

Mathematics

2 answers:

Mashcka [7]3 years ago

7 0

Yea I’m pretty sure they do because I be having a lot of school books during the year I’m not going to lie

34kurt3 years ago

5 0

A = 100 and i’m not exactly sure what b equals (i’m new to this so i’m sorry if my answer was un-necessary)

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Jemer lost his ball and decided to buy a new one. the new ball cost $300. which is three times the price of his old ball. how mu

shusha [124]

Answer:

The cost of the old ball was $100.

Step-by-step explanation:

The cost of the new ball = $300

The new ball has three times the price of his old ball.

So, let the price of the old ball be = x

As per situation, we get the equation:

$3x=300$

Dividing both sides by 3:

$\frac{3x}{3}= \frac{300}{3}$

=> x = 100

Hence, the cost of the old ball was $100.

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3 years ago

Find the area of the shaded segment. Round your answer to the nearest square centimeter. Will make brainliest answer if correct

allochka39001 [22]

First find the area of the circle using A=pi*r^2
pi*36
Then divide this by 4 because the shaded region is 1/4 of the circle
(36*pi)/4=9*pi
Final answer: B

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3 years ago

For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.