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Andreyy89
3 years ago
9

What is the probability of rolling a number less than or equal to eight with the sum of two dice, given that at least one of the

dice must show a 6?

Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

4/11

Step-by-step explanation:

Outcomes that meet your requirement are

 (1, 6), (2, 6), (6, 1), (6, 2)

for a total of 4 favorable outcomes.

There are 11 outcomes in which one die shows a 6.

So your probability would be 4/11.

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-28 + 5b = 4 (6b + 9) = There are no options i need it now
Kamila [148]

Answer:

see the attachment and Mark as brainleist plz

4 0
3 years ago
Read 2 more answers
Help me please i don't know what to do
astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

(x-7)(x+2) = 0

FOIL:

x^2 + 2x - 7x - 14 = 0

Simplify:

x^2 - 5x - 14 = 0

a = 1, b = -5, c = -14

b. one x-int at 3

this means that the equation will factor to:

(x-3)^2=0

FOIL:

x^2 - 3x - 3x +9 = 0

Simplify:

x^2 - 6x + 9 = 0

a = 1, b = -6, c = 9

c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

-x^2-x-3=0

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

(x+1)(x-1)=0

This is a perfect square

FOIL:

x^2-1=0

a = 1, b = 0, c = -1

e. x-int at \sqrt{3} , -\sqrt{3}

our equation will factor to:

(x+\sqrt{3} )(x-\sqrt{3)} =0

This is also a perfect square

FOIL and you will get:

x^2 - 3 = 0

a = 1, b = 0, c = -3

4 0
2 years ago
Does Anyone know this?
lukranit [14]

Answer:

∠AEC = 139°

Step-by-step explanation:

Since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1

∠AED = ∠AEB + ∠BEC + ∠CED = 180 ← straight angle

Substitute values into the equation

11x - 12 + 4x + 1 + 4x + 1 = 180, that is

19x - 10 = 180 ( add 10 to both sides )

19x = 190 ( divide both sides by 19 )

x = 10

Hence

∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11, hence

∠AEC = (15 × 10) - 11 = 150 - 11 = 139°

6 0
3 years ago
Let f(x)= -5x+10 then f(-2)=<br><br> Simple functions
valentina_108 [34]
F(x) = -5 x + 10
Then
f(-2) = -5(-2) + 10
= 10 + 10
= 20
8 0
3 years ago
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If 9 + 10 = 21 <br><br> What’s 10 + 9?
Gala2k [10]
Answer: is still 21
8 0
2 years ago
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