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Andreyy89
2 years ago
9

What is the probability of rolling a number less than or equal to eight with the sum of two dice, given that at least one of the

dice must show a 6?

Mathematics
1 answer:
Daniel [21]2 years ago
6 0

Answer:

4/11

Step-by-step explanation:

Outcomes that meet your requirement are

 (1, 6), (2, 6), (6, 1), (6, 2)

for a total of 4 favorable outcomes.

There are 11 outcomes in which one die shows a 6.

So your probability would be 4/11.

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Adam works at a bakery. He uses 1/8 of his flour supply to make bread and 3/4 of his flour supply to make other baked goods. If
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Answer: B  

he has 24 in his supply!

Step-by-step explanation:

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3 years ago
CAN SOMEONE HELP ME​
ANTONII [103]

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C is the answer

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3 years ago
Help would be appreciated ( Grade 4 homework )
saul85 [17]

9514 1404 393

Answer:

 (B)  4

Step-by-step explanation:

Consider the units column. The only sum of 3 and a single digit that will end in 1 is the sum ...

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This tells you A = 8, so the top number is 1983, and the middle number is B78.

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3 0
3 years ago
Read 2 more answers
6,528 divided by 8 and also 6,349 divided by 9
mote1985 [20]

Answer:

6,528 divided by 8 is 816

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6348 divide by 9 is 705.44..... ♾️

7 0
2 years ago
2 1/2r + 1 + 2r = 9 1/10
GalinKa [24]

This should help you here are the steps of your problem :)


2*(1/2)*r+2*r+1 = 9*(1/10) // - 9*(1/10)


2*(1/2)*r+2*r-(9*(1/10))+1 = 0


2*(1/2)*r+2*r-9/10+1 = 0


3*r+1/10 = 0 // - 1/10


3*r = -1/10 // : 3


r = -1/10/3


r = -1/30


r = -1/30


So your answer would be 1/30

4 0
3 years ago
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