we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
brainly.com/question/17297081
#SPJ1
Answer:
A. True
B. True
C. False
Step-by-step explanation:
Hope that helps!
Answer:
1.Yes
2.No
3.No
4.Yes
Step-by-step explanation:
Answer:
(2,0), (-5,0)
Step-by-step explanation:
I'm not sure if this is correct or not, but going off of what they had for points J and K, I think it's the best answer.
Erm
x+y=6
xy=12
x+y=6
y=6-x
sub back
xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i
x=3+/-i√3
the numbers are 3+i√3 and 3-i√3
no real numbers tho
