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3 years ago

What is the solution to the following system?

Mathematics

1 answer:

GalinKa [24]3 years ago

5 0

Answer:

(2, - 6, 3) 

Step-by-step explanation:

2x - y - 3z = 1 ⇒ y = 2x - 3z - 1 .... (1)

4x + 3y + 2z = - 4 .... (2)

- 3x + 2y + 5z = - 3 .... (3)

(1) ---> (2) and (3)

4x + 3(2x - 3z - 1) + 2z = - 4 ⇔ 10x - 7z = - 1 ... (4)

- 3x + 2(2x - 3z - 1) + 5z = - 3 ⇔ x - z = - 1 ⇒ x = z - 1 ---> (4)

10(z - 1) - 7z = - 1 ⇒ z = 3

x = 2

2(2) - y - 3(3) = 1 ⇒ y = - 6

(2, - 6, 3)

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. Here is an equation 2x + 9 = -15. Write three different equations that have the same solution as 2x + 9 = -15. Show or explain

Anettt [7]

Answer:

1. $x-3=-15$
2. $2x=-24$
3. $2x-3=-27$

Step-by-step explanation:

Given the following question:

$2x+9=-15$

To find three equations that have the same solution as the given equation we have to first solve the equation.

$2x+9=-15$
$9-9=0$
$-15-9=-24$
$2x=-24$
$2x\div2=x$
$-24\div2=-12$
$x=-12$

Equation one:
$x-3=-15$
$-3+3=0$
$-15+3=-12$
$x=-12$

Equation two:
 $2x=-24$
$2x\div2=x$
$-24\div2=-12$
$x=-12$

Equation three:
$2x-3=-27$
$-3+3=0$
$-27+3=-24$
$-24\div2=-12$
$x=-12$

Hope this helps.

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