Answer : The grams of
consumed is, 89.6 grams.
Solution : Given,
Mass of
= 265 g
Molar mass of
= 80 g/mole
Molar mass of
= 28 g/mole
First we have to calculate the moles of
.
![\text{Moles of }CaCN_2=\frac{\text{Mass of }CaCN_2}{\text{Molar mass of }CaCN_2}=\frac{265g}{80g/mole}=3.2moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DCaCN_2%3D%5Cfrac%7B%5Ctext%7BMass%20of%20%7DCaCN_2%7D%7B%5Ctext%7BMolar%20mass%20of%20%7DCaCN_2%7D%3D%5Cfrac%7B265g%7D%7B80g%2Fmole%7D%3D3.2moles)
The given balanced reaction is,
![CaC_2+N_2\rightarrow CaCN_2+C](https://tex.z-dn.net/?f=CaC_2%2BN_2%5Crightarrow%20CaCN_2%2BC)
from the reaction, we conclude that
As, 1 mole of
produces from 1 mole of ![N_2](https://tex.z-dn.net/?f=N_2)
So, 3.2 moles of
produces from 3.2 moles of ![N_2](https://tex.z-dn.net/?f=N_2)
Now we have to calculate the mass of ![N_2](https://tex.z-dn.net/?f=N_2)
![\text{Mass of }N_2=\text{Moles of }N_2\times \text{Molar mass of }N_2](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DN_2%3D%5Ctext%7BMoles%20of%20%7DN_2%5Ctimes%20%5Ctext%7BMolar%20mass%20of%20%7DN_2)
![\text{Mass of }N_2=(3.2moles)\times (28g/mole)=89.6g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DN_2%3D%283.2moles%29%5Ctimes%20%2828g%2Fmole%29%3D89.6g)
Therefore, the grams of
consumed is, 89.6 grams.