1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DiKsa [7]
2 years ago
7

Mechanism of this reaction​

Chemistry
1 answer:
Leni [432]2 years ago
3 0

Answer:

A reaction mechanism is the sequence of elementary steps by which a chemical reaction occurs. A reaction that occurs in two or more elementary steps is called a multistep or complex reaction. ... The slowest step in a reaction mechanism is known as the rate-determining step.

You might be interested in
Why is oxygen crucial to living things?
KATRIN_1 [288]
Oxygen is something that activated Cellar Reapiration that convets nutrients into energy (ATP).
6 0
3 years ago
What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

4 0
3 years ago
Scientists use what properties to help them identify and classify matter
Volgvan
Scientists use the physical and chemical properties to help them identify and classify matter. These physical and chemical properties are in a macro-perspective, in which these matter contains compounds, elements and atoms. Hence, matter can be classified in various ways, <span><span>
1.    </span>Atomic number either atomic mass each element has</span> 
<span><span>2.    </span>By substance of that matter either pure substance or mixed substance</span> <span>
3.    If they cannot reduce a certain substance into a much smaller quantified atomic structure then they they’ll use (2) to identify and classify it.</span>
5 0
3 years ago
Which technology was essential for the development of the cell theory?​
vodka [1.7K]

Answer: Microscope

Explanation: This is a kid answering :)

8 0
3 years ago
IBNEED HELP ASAP<br> NO BULL I NEED ACTUAL HELP
Alja [10]

Answer:

god says dont use any assault language okay?

Explanation:

5 0
3 years ago
Other questions:
  • Definition of sound waves
    13·1 answer
  • If 2 objects have the same mass of 100 grams and object A has a volume of 50cm 3 and object B has a volume of 200 cm 3, which of
    15·1 answer
  • What defines endothermic reactions and exothermic reactions? Select all that apply.
    5·2 answers
  • 24. A hypothesis cannot be considered a
    5·2 answers
  • When a solvent can dissolve no more of a solid solute at a specific temperature, we say the solution is
    12·1 answer
  • What do electrons Do in ionic bond? Do they transfer from metals to no metals or nonmetal to metals?
    6·1 answer
  • WANT A FRIEND? CHOOSE ME!!!
    10·1 answer
  • Which ionic compound would you predict to have a higher boiling point: NaBr or
    14·1 answer
  • Help plssss no linkkkkk
    11·2 answers
  • -HELP-<br>How many molecules are contained in 125 grams of oxygen gas (O2)?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!