Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
<h2><u>Solution</u>:-</h2>
Hypotenuse (x) of the right triangle = 
Hypotenuse (x) of the right triangle = 
Hypotenuse (x) of the right triangle = 
Hypotenuse (x) of the right triangle = 13
The hypotenuse (x) of the right triangle is <u>1</u><u>3</u><u> </u><u>m</u>.
<h3>Hence, option (D) <u>1</u><u>3</u><u> </u><u>m</u> is correct. [Answer]</h3>
For this case we have the following equation:

To clear w, we must follow the following steps:
1) The value of t multiplied by c pass to divide the other side of the equation:
2) the value of 1000 is passed to multiply to the other side of the equation:
Answer:
The cleared equation for w is:
Answer:
I think it A I know it try a

÷

First, apply this following rule:

÷

×


×
Second, apply this following rule:

×

Third, multiply 1 × 6 to get 6 and 6 × 2 to get 12.
Fourth, find the GCF of 6 and 12.
Factors of 6: 1, 2, 3, 6
Factors of 12: 1, 2, 3, 4, 6, 12
The GCF is 6.
Fifth, divide the numerator by the GCF.

÷
Sixth, divide the denominator by the GCF.

÷
Seventh, collect the new numerator and new denominator.

Answer as fraction:

Answer as decimal: 0.5