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shusha [124]
3 years ago
9

Which of the following is irrational? 2 v1.44 1

Mathematics
1 answer:
kkurt [141]3 years ago
3 0

Answer:

B

Step-by-step explanation:

B

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What is 7y divided by 12 minus 84
Westkost [7]

Answer:

1/y -84

Step-by-step explanation:

7y/12-84

simplify= 1/y-84

8 0
3 years ago
What is the relationship between the lines determined by the following two equations?
oksano4ka [1.4K]

Answer:

C. They are the same line.

Step-by-step explanation:

In order to compare the linear equations given, they need to be in the same form.  The best form in order to evaluate slope and y-intercept is slope-intercept form, y = mx + b.  Since the second equation is already in slope-intercept form, we need to use inverse operations to convert the first equation:

6x - 2y = 16 ----  6x - 2y - 6x = 16 - 6x ----  -2y = -6x + 16

-2y/-2 = -6x/-2 + 16/-2

y = 3x - 8

Since both equations are in the form y = 3x - 8, then they are both the same line.

4 0
3 years ago
6. Jake jumped 3 feet. Marco jumped
cestrela7 [59]
They jumped 2 feet more as Jake + Peter = 7 so 7-5=2
4 0
2 years ago
Kendra was asked to find the number of students who planned to attend the evening symphony performance. She was told that 40 per
navik [9.2K]

Picture related to the question is attached below

Answer:

Kendra should have divided by 2 instead of multiplying by 2

Step-by-step explanation:

40 percent = percentage who plan to attend

100% = total percentage of student

From the question ;

When reducing percentages, division is employed and this the equation should be :

40/2 ÷ 100/2

40/2 * 2/100

20 * 1/50

20/50

= 0.4

0.4 * 50

= 20 students

6 0
2 years ago
Read 2 more answers
Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)
USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
     = 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0
3 years ago
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