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tresset_1 [31]
3 years ago
9

Write the equation of a line that is

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

Answer:

y=0.5x-5

Step-by-step explanation:

Since the equation is parallel, this means that the slope remains the same which is 0.5.

The remaining thing to do is to find b or y-intercept. To do that, the point (6,-2) and the slope of 0.5 will be used.

-2=0.5(6)+b

When solving for b, it will equal to -5.

Therefore the new equation that is parallel is y=0.5x-5

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Write as a unit rate. $300 per 6 hours. A 50 hours per dollar B $50 per hour C $0.20 per hour D 0.2 hours per dollar
jonny [76]
The correct answer is B) $50 per hour. Hope this helps!
4 0
3 years ago
(4x2 - 10x -24) (2x + 3)
jeyben [28]

Answer:

Apply BODMAS

Step-by-step explanation:

PLEASE FIND THE PICTURE BELLOW

SOLUTION STEPS

(4⋅2−10x−24)(2x+3)

Multiply 4 and 2 to get 8.

(8−10x−24)(2x+3)

Subtract 24 from 8 to get −16.

(−16−10x)(2x+3)

Apply the distributive property by multiplying each term of −16−10x by each term of 2x+3.

−32x−48−20x  

2

−30x

Combine −32x and −30x to get −62x.

−62x−48−20x  

2

3 0
2 years ago
1 ringtone and $3 equals $4, how much is the ringtone​
gavmur [86]

Answer:

$1

Step-by-step explanation:

Let's call the ringtone r. If the ringtone and $3 equals $4, then we can write the equation $4=$3+r. To solve, all you have to do is isolate the r by subtracting 3 on each side.

5 0
3 years ago
N-7=-16%8%9 don't get ittt
VLD [36.1K]
N=6.8848 is yours .-.
6 0
3 years ago
A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
solmaris [256]

Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

Volume is given by  

V = V = Length\times Width\times Height\\V = (30 - 2x)(15-2x)x= 4x^3-90x^2+450x\\So,\\V(x) = 4x^3-90x^2+450x

First, we differentiate V(x) with respect to x, to get,

\frac{d(V(x))}{dx} = \frac{d(4x^3-12x^2+9x)}{dx} = 12x^2 - 180x +450

Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

Solving, with the help of quadratic formula, we get,

x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

Again differentiation V(x), with respect to x, we get,

\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

\displaystyle\frac{5(3-\sqrt{3})}{2},

\frac{d^2(V(x))}{dx^2} < 0

Thus, by double derivative test, the maxima occurs at

x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

V(\displaystyle\frac{5(3-\sqrt{3})}{2}) = (30 - 2x)(15-2x)x = 649.5191\text{ cubic inches}

8 0
3 years ago
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