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Bond [772]
3 years ago
12

Find the missing sides. (Help me)

Mathematics
1 answer:
slavikrds [6]3 years ago
3 0

Answer:

2nd one

Step-by-step explanation:

when it's a 45 45 and 90 triangle, it's 1, 1, sqrt 2, but now since the 1 is sqrt 2, v is sqrt 2, and u and sqrt 2 times sqrt 2, which is 2

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Assume that y varies with x. when y=6, x=2/3. what is x when y=12? NEED QUICK!!
liraira [26]

Answer:

4/3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can anyone help me I did it I'm just checking :)
lukranit [14]

Answer:

<h2>x = 12</h2><h2 />

Step-by-step explanation:

2x + 5 = 3x - 7

5 + 7 = 3x - 2x

12 = x

8 0
2 years ago
Reduce in standard form -3/-15. on rational no grade 8 with step by step solution ​
sashaice [31]

Answer:

i'm not too good in this, but i believe the answer is -3

Step-by-step explanation:

the hcf, highest common factor, of both -3 and -15 is -3, hence making the answer -3? if this is incorrect, i apologize.

3 0
1 year ago
PLZ HELP! Need this rlly bad! Will mark Brainliest! Thx so much!
sashaice [31]

Plot the given point B(3,5) and a vertical line through it:

Next draw several possibilities for A(x,3), for instance

A(-4,3), A(-1,3), A(1,3), and A(5,3

Draw a line through them:

Now you can see that the only value of x is the value where the

blue line crosses the green vertical line, which is at A(3,3)

could you mark Brainy PLS


7 0
3 years ago
La barbería El Caleño, tiene en promedio 120 clientes a la semana a
Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

                     120 = -85.71 + b

                     120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

7 0
2 years ago
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