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3 years ago

What is different between margerine and butter in term of organic chemistry

Chemistry

1 answer:

Brut [27]3 years ago

4 0

Answer:

The most important difference between the two is that butter is derived from dairy and is rich in saturated fats, whereas margarine is made from plant oils. ... If the margarine contains partially hydrogenated oils, it will contain trans fat, even if the label claims that it has 0 g.

Explanation:

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The combustion of 1.38 grams of a compound which contains C, H, O and N yields 1.72 grams of CO2 and 1.18 grams of H2O. Another

I am Lyosha [343]

Answer:

The empirical formula is C3H10N2O2

Explanation:

Step 1: Data given

Mass of the sample in experiment 1 = 1.38 grams

Mass of CO2 produced = 1.72 grams

Mass of H2O produced = 1.18 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Atomic mass C = 12.01 g/mol

Atomic mass O = 16.0 g/mol

Atomic mass H = 1.01 g/mol

MAss of the sample in experiment 2 = 22.34 grams

Mass of O = 6.75 grams

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 1.72 grams / 44.01 g/mol

Moles CO2 = 0.0391 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.0391 moles CO2 we have 0.0391 moles C

Step 4: Calculate mass C

Mass C = 0.0391 moles * 12.01 g/mol

Mass C = 0.470 grams

Step 5: Calculate moles H2O

Moles H2O = 1.18 grams / 18.02 g/mol

Moles H2O = 0.0655 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.0655 moles H we have 2*0.0655 = 0.131 moles H

Step 7: Calculate mass H

Mass H = 0.131 moles * 1.01 g/mol

Mass H = 0.132 grams

Step 8: Calculate the mass %

% C = (0.470 grams / 1.38 grams) * 100 %

% C = 34.06 %

%H = (0.132/1.38)*100 %

%H = 9.57 %

%O= (6.75 grams / 22.34 grams)*100 %

%O = 30.21 %

%N = 100 % - 34.06 % - 9.57 % - 30.21 %

%N = 26.16 %

Step 8: Calculate moles in compound

Let's assume 100 grams sample then we have:

Mass C = 34.06 grams

Mass H = 9.57 grams

Mass O = 30.21 grams

Mass N = 26.16 grams

Moles C= 34.06 grams / 12.01 g/mol

Moles C= 2.836 moles

Moles H = 9.57 grams / 1.01 g/mol

Moles H = 9.475 moles

Moles O = 30.21 grams / 16.0 g/mol

Moles O = 1.888 moles

Moles N = 26.16 grams / 14.0 g/mol

Moles N = 1.869 moles

Step 9: Calculate mol ratio

We have to divide by the smallest amount of moles

C: 2.836 moles / 1.869 moles = 1.5

H: 9.475 moles /1.869 moles = 5

O: 1.888 moles /1.869 moles = 1

N: 1.869 moles / 1.869 moles = 1

This means for each mol O we have 1.5 moles C, 5 moles H and 1 mol N

For every 2 O atoms we have 3 C atoms, 10 H atoms and 2 N atoms

The empirical formula is C3H10N2O2

6 0

3 years ago

Complete combustion of 9.00 g of a hydrocarbon produced 28.9 g of co2 and 9.87 g of h2o. what is the empirical formula for the h

AVprozaik [17]

DnsigshsjeshsinVshzivfbtofns

8 0

3 years ago

What mass of water must be added to 5g of nacl to make 5% mass persentage of the solution?

Vitek1552 [10]

Answer:-

95 grams

Explanation:-

Let the mass of water to be added be M

So total mass = 5 + M

So 5% of this solution has 5g of NaCl by mass.

∴ (M+5) x (5/100) = 5

M+5 = 5 x 100/5

M+5=100

M= 100-5

So amount of water to be added is 95 gram

8 0

3 years ago

B) Ethane has the formula C2H6. In terms of electronic structure,

k0ka [10]

Answer:

There is one single covalent bond between two carbon atoms.

Explanation:

We know that sharing of electrons form covalent bonds.

If we look upon K,L,M ,N shells of the carbon and hydrogen atoms.

We found that Hydrogen is having only $1$ electron in K shell.

And Carbon on the other hand is having $2$ electrons in K shell and $4$ electrons in L shell.

So carbon have $4$ valence electrons,and it can share $4$ bonds with any relevant atom to complete its octet.

And Hydrogen requires $1$ electron to complete its doublet.

Alkane general formula $C_{n}H_{2n+2}$

For ethane $n=2$

$C_{2}H_{4+2}$ $=$ $C_{2}H_{6}$

$1$ Carbon atom is shared by $3$ Hydrogen.

The remaining one electron $(4-3)=1$ of carbon will be shared with another carbon atom.

An image of the sharing of electrons attached below,

Hence we have only $1$ covalent bond between the two.

5 0

3 years ago

A quantity that had just a number

Mama L [17]

Answer:

Explanation:

4 0

3 years ago