2CO (g) + O2 (g) → CO2 (g) How many grams of O2 are needed to react with 6.64 L of CO2?

What is reacitivty series, and how you can access reactivity of metals...

lubasha [3.4K]

In Chemistry, a reactivity series of metals , also known as the activity series refers to the arrangement of metals in the descending order based upon their reactivity .

Salient Features :-

The metal at the top of the reactivity series are powerful reducing agents since they are easily oxidized.
The reducing ability of metals grows weaker while traversing down the series.
The electro-positivity of metals also reduces while moving down the reactivity series.
Metals that are placed higher on the reactivity series have the ability to displace metals that are placed lower in the series.

The metal reactivity series is given below :-

To access the reactivity of metal , from the given reactivity series identify any of the metal and locate the reactivity based upon the choice of reactivity. The metal at the top (Potassium) is most reactive and the metal at the bottom (Platinum) is the least reactive.

To learn more about metal reactivity series visit -

brainly.com/question/16072297

8 0

2 years ago

Determine the oxidation numbers of all the elements in the unbalanced reactions. Then, balance each redox reaction in a basic so

givi [52]

Answer for 1:

- Oxidation number of Mn in MnO4^-1= +7

- Oxidation number of O in MnO4^-1= -2

- Oxidation number of C in C2O4^-2= +3

- Oxidation number of O in C2O4^-2= -2

- Oxidation number of Mn in MnO2= +4

- Oxidation number of O in MnO2= -2

- Oxidation number of C in CO2= +4

- Balanced redox equation in basic solution:

$3C_2O_4^{-2}+2MnO_4^{-1}+4H_2O\operatorname{\rightarrow}6CO_2\text{ +}2MnO_2\text{ + }8OH^-$

Explanation for 1:

1st) To determine the oxidation numbers, it is necessary that the total sum of the charges is equal to that of the molecule or ion in the equation.

• Oxidation numbers in MnO4-,:

We know that the oxidation number for oxygen is -2, then we multiply it by the subscript 4 to find the whole charge of oxygen in this molecule.

Oxygen oxidation number: -2 x 4 = -8

Since the total charge of the molecule is -1, by difference, we will know that the oxidation number of Mn will be +7:

$\begin{gathered} Mn^{+7}O_4^{-2} \\ +7+[(-2*4)]=-1 \end{gathered}$

To confirm that the oxidation number that we determined exists for that element, we can check the Periodic Table of Elements.

We proceed in the same way with all molecules.

• Oxidation numbers in C2O4-2,:

$\begin{gathered} C_2^{+3}O_4^{-2} \\ (+3*2)+[(-2)*4]= \\ +6-8=-2 \end{gathered}$

• Oxidation numbers in MnO2,:

$\begin{gathered} Mn^{+4}O_2^{-2} \\ +4+[(-2)*2]= \\ +4-4=0 \end{gathered}$

• Oxidation numbers in CO2,:

$\begin{gathered} C^{+4}O_2^{-2}_ \\ +4+[(-2)*2]= \\ +4-4=0 \end{gathered}$

2nd) Now that we know the oxidation number os each atom in the reaction, then we can find the element that is oxidized and the element that is reduced.

We can see that Mn goes from +7 to +4, the Mn atom is reduced. And, the carbon atom goes from +3 to +4 so it oxidizes.

3rd) It is necessary to write the oxidation reaction and the reduction reaction separately and balancing all elements except oxygen and hydrogen:

Oxidation:

$C_2O_4^{-2}\text{ }\rightarrow\text{ 2}CO_2\text{ + 2}e^-_$

Reduction:

$MnO_4^{-1}\text{ + 3}e^-\rightarrow MnO_2$

4th) Since the reaction occurs in a basic solution, we must add water (H2O) to balance the oxygen atoms and hydroxyl ion (OH-) to balance the hydrogen atoms. In this case, the reduction reaction is the only one that needs to be balanced with water and hydroxyl ion.

$MnO_4^{-1}\text{ + 3}e^-\text{ +2}H_2O\operatorname{\rightarrow}MnO_2\text{ + 4}OH^-$

5th) It is necessary to balance the electrons in each half-reaction. So, we multiply each half-reaction by the number of electrons in the other half-reaction:

Oxidation:

$\begin{gathered} (C_2O_4^{-2}\operatorname{\rightarrow}\text{2}CO_2\text{ + 2}e_^-)*3 \\ 3C_2O_4^{-2}\operatorname{\rightarrow}6CO_2\text{ + 6}e^- \end{gathered}$

Reduction:

$\begin{gathered} (MnO_4^{-1}\text{ + 3}e^-\text{ + 2}H_2O\operatorname{\rightarrow}\text{ MnO}_2\text{ }+4OH^-)*2 \\ 2MnO_4^{-1}\text{ + 6}e^-\text{ + 4}H_2O\operatorname{\rightarrow}\text{ 2MnO}_2\text{ }+8OH^- \end{gathered}$

6th) We need to cancel out everything that is repeated on opposite sides of the reactions, including the electrons.

Finally, we can write the balanced redox equation:

$3C_2O_4^{-2}+2MnO_4^{-1}+4H_2O\operatorname{\rightarrow}6CO_2\text{ +}2MnO_2\text{ + }8OH^-$

6 0

1 year ago

Which of these is a mixture? Carbon Carbon dioxide Air Oxygen

pashok25 [27]

Air is the mixture of many gasses.

7 0

3 years ago

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The identity of an element depends on the number of protons and neutrons in the nucleus. protons in the atom. neutrons in the at

labwork [276]

Answer:

protons in the atom.

Explanation:

The identity of an element relies on the number of protons in its atom. This is called the atomic number. The atomic number is the basis of the periodic table of elements. Modern periodic law states that "the properties of elements are a periodic function of their atomic number".

Atomic number of atoms do not change and they are convieniently used in identifying an atom.

8 0

3 years ago

Por qué los materiales generan una llama de distinto color?

serg [7]

Answer:

El color de la llama se debe a que los átomos del metal absorben energía de la llama; dicha energía se transforma en luz cuando el átomo vuelve a su estado normal. Los agentes productores del color se usan en forma de sales y raramente como metales en polvo

Explanation:

5 0

3 years ago

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