Chlorine gas (cl2) forms when two chlorine atoms share an electron. what type of bonding is present in chlorine gas?
2 answers:
Explanation:
When a chemical bond is formed by sharing of electrons then it is known as a covalent bond.
A covalent bond is always formed between two non-metals.
For example, atomic number of chlorine is 17 and its electronic distribution is 2, 8, 7.
As a result, it needs one more electron to complete its octet. So, when it chemically combines with another chlorine atom then there will occur sharing of electrons.
Hence, is formed which is a covalent compound.
On the other hand, when a chemical bond is formed by transfer of electrons from one atom to another then it is known as an ionic bond. An ionic bond is always formed between a metal and a non-metal.
For example, LiCl is an ionic compound.
Thus, we can conclude that in a chlorine gas covalent bonding is present when two chlorine atoms share an electron.
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Answer :
The equilibrium concentration of CO is, 0.016 M
The equilibrium concentration of Cl₂ is, 0.034 M
The equilibrium concentration of COCl₂ is, 0.139 M
Explanation :
The given chemical reaction is:
Initial conc. 0.1550 0.173 0
At eqm. (0.1550-x) (0.173-x) x
As we are given:
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
x = 0.139 and x = 0.193
We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.
Thus, we are taking value of x = 0.139
The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M
The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M
The equilibrium concentration of COCl₂ = x = 0.139 M