The grams of oxygen that are produced is 228.8 grams
<em>calculation</em>
2H₂O₂ → 2H₂O +O₂
Step 1: use the mole ratio to determine the moles of O₂
from equation above H₂O₂:O₂ is 2:1
therefore the moles of O₂ = 14.3 moles ×1/2 = 7.15 moles
Step 2: find mass of O₂
mass = moles × molar mass
= 7.15 moles × 32 g/mol =228.8 g
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The volume occupied by the gas in the container is 1 m³
Boyles law applies
P₁ V₁ = P₂ V₂
Where P₁ = 200kpa
P₂ = 300kpa
if its initial volume is 1.5
then,
P₁ V₁ = P₂ V₂
200 × 1.5 = 300 × V₂
V₂ = 200 × 1.5 / 300
= 1 m³
Hence the volume occupied by the gas container is 1 m³
Learn more about the Boyles law on
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<u>We are given:</u>
Mass of ice = 21 grams
The ice is already at 0°c, the temperature at which it melts to form water
Molar heat of fusion of Ice = 6.02 kJ/mol
<u>Finding the energy required:</u>
<u>Number of moles of Ice: </u>
Molar mass of water = 18 g/mol
Number of moles = given mass/ molar mass
Number of moles = 21 / 18 = 7/6 moles
<u>Energy required to melt the given amount of ice:</u>
Energy = number of moles * molar heat of fusion
Energy = (7/6) * (6.02)
Energy = 7.02 kJ OR 7020 joules
