The electron geometry is tetrahedral and the molecular geometry is tetrahedral. If a molecule of CH3OCH3 is to be drawn, the two carbons would have four single bonds and the middle O would have two single bonds and the two lone pairs. Molecular geometry does not consider the lone pairs as bonds like in electron domain geometry. However, since the carbons do not contain any lone pairs, its electrons domain and molecular geometry will be the same. Therefore; Both carbons are tetrahedral for electron domain geometry and molecular geometries. The O is tetrahedral for the electron domain geometry and bent for molecular geometry.
Answer:
≈194.7
Explanation:
(547cm^3/590K) / (V2/210K)
V2 = 194.69 or 194.7
:D
