Answer:
Proper waste management allows for separation at the source and subsequent recycling, which allows materials that required energy and raw materials to be reincorporated into the production cycle, as the finished material is incorporated back into the production cycle, the amount of energy required for the production of <u>the final product is less than if it were made from the start</u>.
Explanation:
A very useful example of energy conservation through waste management is the following: suppose that in your school they do proper waste management, therefore materials such as cardboard, paper and plastic are separated appropriately and are subsequently donate or sell to a company that is dedicated to recycling these materials, plastic is a material that requires a lot of energy, first for its elaboration and later for the creation of the final product such as the packaging of a shampoo or a chair, however, as the recycled plastic is already manufactured, <u>the recycling company saves said energy, which only requires crushing the obtained plastic and selling it to a company that produces the final product</u>.
The gas is disposed proportional to the temperature to pressure of the particles
Answer:
I think it's A because effusion is a gas escaping from a tiny hole
Explanation:
I just finished the test and got it right :)
Answer:
The pH is 8,45 and it is basic.
Explanation:
The pH is a measure that gives us an idea of the acidity or alkalinity of a solution. It is calculated as:
pH = -log (H +)= -log (0.0000000035)=8, 46
The pH scale ranges from values of 0 to 14 (less than 7.0 is acidic and greater than 7.0 is basic, a pH = 7.0 is neutral).
In this case, the solution is basic (value greater than 7.0 ).
Answer:
0.165 mol·L⁻¹
Explanation:
1. Write the <em>chemical equation</em> for the reaction.
HNO₃ + KOH ⟶ KNO₃ + H₂O
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2. Calculate the <em>moles of HNO₃</em>
c = n/V Multiply each side by V and transpose
n = Vc
V = 0.027 86 L
c = 0.1744 mol·L⁻¹ Calculate the moles of HNO₃
Moles of HNO₃ = 0.027 86 × 0.1744
Moles of HNO₃ = 4.859 × 10⁻³ mol HNO₃
===============
3. Calculate the <em>moles of KOH
</em>
1 mol KOH ≡ 1 mol HNO₃ Calculate the moles of KOH
Moles of KOH = 4.859 × 10⁻³× 1/1
Moles of KOH = 4.859 × 10⁻³ mol KOH
===============
4. Calculate the <em>molar concentration</em> of the KOH
V = 29.4 mL = 0.0294 L Calculate the concentration
c = 4.859 × 10⁻³/0.0294
c = 0.165 mol·L⁻¹
