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3 years ago

GIVING BRAINIEST THIS IS 6TH GRADE LEVEL MATH!

1 answer:

3 0

if you divide a number by 2 then you would probably end up with a whole number but if you divide a number by 1/2 you will end up with a fraction

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Mara had 7 cookies.She ate some Now she has 4 cookies. How many cookies did she eat? Draw a tape diagram

Westkost [7]

Mara ate 3 cookies because you subtract

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3 years ago

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Alyssa is driving to Chicago, and she is traveling at 60 miles per hour. If Chicago is 96 miles away, how long will it take her

Leviafan [203]

Answer: C

Step-by-step explanation: 1hour 36minutea

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3 years ago

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Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a

Vitek1552 [10]

Answer:

$2ab - 6a + 5b - 15$

Step-by-step explanation:

Given

$2ab - 6a + 5b + \_$

Required

Fill in the gap to produce the product of linear expressions

$2ab - 6a + 5b + \_$

Split to 2

$(2ab - 6a) + (5b + \_)$

Factorize the first bracket

$2a(b - 3) + (5b + \_)$

Represent the _ with X

$2a(b - 3) + (5b + X)$

Factorize the second bracket

$2a(b - 3) + 5(b + \frac{X}{5})$

To result in a linear expression, then the following condition must be satisfied;

$b - 3 = b + \frac{X}{5}$

Subtract b from both sides

$b - b- 3 = b - b+ \frac{X}{5}$

$- 3 = \frac{X}{5}$

Multiply both sides by 5

$- 3 * 5 = \frac{X}{5} * 5$

$X = -15$

Substitute -15 for X in $2a(b - 3) + 5(b + \frac{X}{5})$

$2a(b - 3) + 5(b + \frac{-15}{5})$

$2a(b - 3) + 5(b - \frac{15}{5})$

$2a(b - 3) + 5(b - 3)$

$(2a + 5)(b - 3)$

The two linear expressions are $(2a+ 5)$ and $(b - 3)$

Their product will result in $2ab - 6a + 5b - 15$

<em>Hence, the constant is -15</em>

3 0

3 years ago

I need to solve this expression

insens350 [35]

Hello,

(-9)⁴= (-9).(-9).(-9).(-9)= 81.81 = 6561

6 0

3 years ago

What is the problem to this

irakobra [83]

4:9
24:x
Set up a proportion
4/9=24/x
4x=216
x=54
a) 54 is your answer
hope this helps, and please give brainliest if it does!

6 0

3 years ago

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