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blagie [28]
3 years ago
10

HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION RQ!!

Mathematics
2 answers:
marta [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Alborosie3 years ago
3 0

Answer:

A is the asnwer because 50percent is too much and anything above 50 is worng so answer is 41percent

Step-by-step explanation:

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If the mean of this data is 95, find the missing data 103,99,90,86,105,96 what is the missing data
d1i1m1o1n [39]
Let, the missing number = x
Then, 103 + 99 + 90 + 86 + 105 + 96 + x / 7 = 95
579+x = 665
x = 665 - 579
x = 86

In short, Your Answer would be 86

Hope this helps!
3 0
3 years ago
Solve the equation.<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7By%5E%7B2%7D-20%2B100%20%7D%20%3Dy-10" id="TexFormula1" title
Lady bird [3.3K]

Answer:

No solution.

Step-by-step explanation:

So lets solve the square root.

Sqrt(y^2 - 20 + 100) = y - 10

Sqrt(y^2 + 80 = y - 10)

Solve time.

y^2 + 80 = y - 10 (We are squaring them)

y^2 + 80 = y^2 - 20y + 100

y^2 + 80 - y^2 = y^2 - 20y + 100 - y^2 (Subtract y^2 from both sides)

80 = -20y + 100

Flip it

-20y + 100 = 80

-20y + 100 - 100 = 80 - 100 (Subtract 100 from both sides)

-20y = -20

Now divide both sides by -20

-20y/-20 = -20/-20

y = 1

All you would do is plug in the values and you get...

9 \neq -9

This is false.

6 0
2 years ago
This please asap asap
Cerrena [4.2K]

Answer: y = -2x + 5

ok done. Thank to me :>

3 0
3 years ago
What are the types of polygons?
Ann [662]

Answer:

Triangle Quadrilateral Pentagon Hexagon Heptagon Octagon Nonagon and Decagon

8 0
3 years ago
Read 2 more answers
Given: ΔABC Prove: The three medians of ΔABC intersect at a common point.
Marta_Voda [28]
<span>Given: ΔABC

When written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point are as follows:

Statements                                                          Justifications

Point F is a midpoint of Line segment AB        </span><span>by Construction               
Point E is a midpoint of Line segment AC
Draw Line segment BE
Draw Line segment FC 

Point G is the point of intersection between
Line segment BE and Line segment FC               Intersecting Lines Postulate

Draw Line segment AG                                        by Construction

Point D is the point of intersection between
Line segment AG and Line segment BC              Intersecting Lines Postulate

Point H lies on Line segment AG such that
Line segment AG ≅ Line segment GH                 by Construction

</span><span>Line segment FG is parallel to line segment
BH and Line segment GE is parallel to line
segment HC                                                         Midsegment Theorem

</span><span><span>Line segment GC is parallel to line segment
BH and Line segment BG is parallel to
line segment HC                                                  Substitution</span>

</span>BGCH is a                                                        <span><span><span><span>Properties of a Parallelogram </span>parallelogram                                                   (opposite sides are parallel)</span>

</span>Line segment BD ≅ Line segment                    </span><span><span>Properties of a Parallelogram </span>DC                                                                    (diagonals bisect each other)   

Line segment AD is a median                          Definition of a Median</span>

Thus the most logical order of statements and justifications is: II, III, IV, I
7 0
3 years ago
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