All categories

4 years ago

PLEASE HELP!! WILL MARK BRAINLIEST AND THANK YOU!!

Mathematics

1 answer:

tangare [24]4 years ago

7 0

Answer:

Option D (-4,7)

Step-by-step explanation:

we have

Square TUVW with vertices T(-6,1), U(-1,0), V(-2,-5), and W(-7,-4

<u><em>The question is</em></u>

Find out the coordinates of U'

Part a) Reflection: in the y-axis

we know that

The rule of the reflection of a point across the y-axis is

(x,y) -----> (-x,y)

U(-1,0) -----> U'(1,0)

Part b) Translation (x,y) —> (x-5,y+7)

That means ---> the translation is 5 units at left and 7 units up

U'(1,0) -----> U''(1-5,0+7)

U'(1,0) -----> U''(-4,7)

therefore

Option D (-4,7)

You might be interested in

Through (5,2) slope=1

LUCKY_DIMON [66]

Answer:

y = x - 3

Step-by-step explanation:

Equation of line in slope point form is given as:

y - y_1 = m(x - x_1)

$y - y_1 = m(x - x_1) \\ y - 2 = 1(x - 5) \\ y - 2 = x - 5 \\ y = x - 5 + 2 \\ y = x - 3 \\$

4 0

3 years ago

A pattern is made from four congruent squares.

Mashutka [201]

Answer:

c is marked on the diagram

3 0

3 years ago

The value of a professional basketball player's autograph rose 20% in the last year. It is now worth $336.00. What was it worth

sesenic [268]

Answer:

The value of basketball player's autograph a year ago is $280

Step-by-step explanation:

Given as :

The present value of autograph = $ 336.00

The rate of increase of autograph = 20%

The time period = 1 year

Let The value one year ago = $ x

So ,

The value of autograph after n year = The present value × $(1+\frac{Rate}{100})^{n}$

Or, $ 336.00 = $ x × $(1+\frac{20}{100})^{1}$

Or, $ 336.00 = $x × 1.2

∴ x = $\frac{336.00}{1.2}$ = $280

Hence The value of basketball player's autograph a year ago is $280 Answer

6 0

3 years ago

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

bixtya [17]

Answer by JKismyhusbandbae: a^n = 4n + 1

Explanation: So the regular formula for sequence is:

an = a1 + d (n – 1)

a1 = the first term.

d = common difference

n = term number

So in the formula form it would look like this: an: 5 - 4(n-1)

Then I like to solve it as if it were a linear equation in the end you get: a^n = 4n + 1

6 0

4 years ago

Find the missing length indicated

Luden [163]

Answer: 9 (now i’m just typing to make it 20 letters)

6 0

3 years ago