3(f − 5) − 9 =

What is the standard form for 600+5+3/100

Y_Kistochka [10]

600+5+3 = 608 / 100 = 6.08

3 0

3 years ago

Would the answer be B or C? I know that their are 6 numbers but It confuses me because two of them are larger!

Travka [436]

Logical u would think it would be 1/6 but not all the pieces are equal so i would go with 1/8

4 0

4 years ago

if the first two statements are true, is the third statement true? 1. all dogs like walks. 2. bandit doesn't like walks. 3. band

Strike441 [17]

If the first two statements are true, then the third statement:

"Bandit is not a dog"

Is true.

<h3>if the first two statements are true, is the third statement true?</h3>

The first statement is:

P = "All dogs like walks"

We assume that this is true, so, if X is a dog, X likes walks.

The second statement is:

Q = "Bandit doesn't like walks"

From this, we only can conclude that Bandit doesn't like walks.

And all dogs like walks, so if Bandit were a dog, he would like walks, but because he does not like walks, we can conclude that Bandit is not a dog.

From that, the third statement:

K = "Bandit is not a dog"

Is true.

So we write that as a conditional statement:

If P and Q ⇒ K

<em>"if all dogs like walks, and Bandit doesn't like walks, then bandit is not a dog".</em>

If you want to learn more about conditional statements:

brainly.com/question/11073037

#SPJ1

3 0

2 years ago

Professor Jennings claims that only 35% of the students at Flora College work while attending school. Dean Renata thinks that th

lisov135 [29]

Answer:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

Step-by-step explanation:

Information given

n=78 represent the random sample taken

X=36 represent the students with jobs

$\hat p=\frac{36}{78}=0.462$ estimated proportion of students with jobs

$p_o=0.35$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the proportion of students with jobs is higher than 0.35, the system of hypothesis are:

Null hypothesis: $p \leq 0.35$

Alternative hypothesis: $p > 0.35$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

5 0

4 years ago

What is 9 3/8 divided by 2 7/8

zzz [600]

75/8 ÷ 23/8
75/8 × 8/23
Both of the 8s will cancel
Answer: 75/23

8 0

3 years ago

Read 2 more answers

3(f − 5) − 9 = –3 f=