Question 1
1 answer:
Answer:
30
Step-by-step explanation:
This problem can be done without the Distance Formula (which is a way to find the distance between any two points in the plane).
The attached image shows the points and segments joining them.
PQ = 5 because the points are on the same horizontal line, and you can count spaces between them (or subtract x-coordinates: 4 - (-1) = 5).
PR = 12 because the points are on the same vertical line; count spaces or subtract y-coordinates, 7 - (-5) = 12.
The triangle is a right triangle, so the Pythagorean Theorem can be used to find the length of the hypotenuse.
The perimeter of the triangle is 5 + 12 + 13 = 30
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Answer:
The coordinates of point A are (-11 , 2)
Step-by-step explanation:
- The coordinates of point P are (-31 , 8)
- The coordinates of point H are (29 , -10)
- Point E is the mid-point of segment PH
- The coordinates of the the mid-point are:
→ and
∵ E is the mid-point of segment PH
∴ The x-coordinate of point E is
∴ The x-coordinate of point E is -1
∴ The y-coordinate of point E is
∴ The y-coordinate of point E is -1
∴ The coordinates of point E are (-1 , -1)
- Point A is graphed of the way along the segment from P to E
- That mean the distances from points P to A is 2 parts and from P to E
is 3 parts, then the distance from A to E is "3 - 2" = 1 part
- So point A divides the line segment PE at ratio 2 : 1 from P
- The coordinates of the division point are:
→ and
∵ Point A divides PE at ratio 2 : 1
∵ The coordinates of point P are (-31 , 8)
∵ The coordinates of point E are (-1 , -1)
∴ The x-coordinate of point A is
∴ The x-coordinate of point A is -11
∴ The y-coordinate of point A is
∴ The y-coordinate of point A is 2
∴ The coordinates of point A are (-11 , 2)
* The coordinates of point A are (-11 , 2)