3 years ago

A triangle can have at most ________ right angle. 0 2 4 1

Mathematics

1 answer:

Archy [21]3 years ago

6 0

Answer:

A positively charged nucleus sits at the center of an atom.

Step-by-step explanation:

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Lincoln invested $49,000 in an account paying an interest rate of 6\tfrac{1}{8}681% compounded daily. Eli invested $49,000 in a

timofeeve [1]

Answer: 15856

Step-by-step explanation: 166786.9963 - 150930.6256

= 15856.3707

= $15856

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2 years ago

I need help with these 2 problems I cant figure out.

Alla [95]

I started by labeling the right angle (Angle C) 90º. Next, I wrote down everything in one equation.

2x + 90 + 3x - 20 = 180º (180 degrees in a triangle)

Next, I add 20 on both sides.

2x + 90 + 3x = 200º

I combine like terms (2x and 3x)

5x + 90 = 200º

I subtract 90 from both sides.

5x = 110º

Divide 110 by 5 to get x.

x = 22

======

For problem two, I label all the angles I know.

49º + 80º + r = 180º

I add 80 and 49.

129º + r = 180º

I subtract 180 and 129 and get 51º, which is your angle for R.

For angle X, you know that angle R plus angle X equals half of a circle, which is 180º

We know from before that 129º is 180º without R, so X is 129º

I hope this helps! Let me know if I'm wrong!

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3 years ago

The temperature in Grand Rapids, Michigan on January 8 was 30 degrees Fahrenheit. The temperature two days later was -8 degrees

EleoNora [17]

The answer is -38 fahrenheit.

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3 years ago

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a factory makes 718 toy trains in one day .the toy trains are placed in boxes of 30 in what place will the first digit of the qu

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The first digit of the quotient is the first number of the answer of your division problem. the answer is 2

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3 years ago

Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia

GrogVix [38]

Answer:

$(\frac{dy}{dt})^2=sin^2t$

Step-by-step explanation:

$y=cost$

DE : $(\frac{dy}{dt})^2=1-y^2$

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

$\frac{dy}{dt}=-sint$

Using the formula

$\frac{d(cosx)}{dx}=-sinx$

LHS: $(\frac{dy}{dt})^2=(-sint)^2=sin^2t$

RHS

$1-y^2=1-cos^2t=sin^2t$

By using the formula

$sin^2t=1-cos^2t$

LHS=RHs

Hence, y is a solution of given DE

$(\frac{dy}{dt})^2=sin^2t$

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3 years ago