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seraphim [82]
3 years ago
6

Matt Ali deposited $25,000 in a savings account. The account earns 5.5 percent interest compounded daily. Use the formula “ Amou

nt of $1.00 at 5.5 Percent compounded Daily”. A). What amount will he have in his account 28 later ? B.) How much will be compound interest ?
Mathematics
1 answer:
katen-ka-za [31]3 years ago
6 0

Answer:

A) Amount = $ 116,601.31

B) Compound Interest = $ 91,601.31

Step-by-step explanation:

Compound interest Formula

A = P(1 + r/n)^nt

Where

P = Initial amount invested = $25,000

r = interest rate = 5.5 %

n = Compounding frequency = daily

t = time in years = 28 years

A). What amount will he have in his account 28 years later ?

First, convert R percent to r a decimal

r = R/100

r = 5.5%/100

r = 0.055 per year,

Then, solve our equation for A

A = P(1 + r/n)^nt

A = 25,000.00(1 + 0.000150685/365)^(365)(28)

A = $ 116,601.31

B.) How much will be compound interest ?

I = Amount - Principal

A(Amount ) = $ 116,601.31

P (principal) = $ 25,000.00

I = $ 116,601.31 - $ 25,000.00

I (interest) = $ 91,601.31

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3 years ago
In Texas, state law requires that for regular classroom settings in elementary grades K-4, the student-to-teacher ratio can be n
Ivenika [448]

Answer:

Step-by-step explanation:

A hypothesis test is performed to determine if the proportion of schools needing such a waiver is above 25%

At the null hypothesis, we test that the proportion is of 25%, that is:

H_0: p = 0.25

At the alternate hypothesis, we test that the proportion is above 25%, that is:

H_a: p > 0.25

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.25 is tested at the null hypothesis:

This means that \mu = 0.25, \sigma = \sqrt{0.25*0.75}

Sample of 85 schools, 32 need a waiver:

This means that n = 85, p = \frac{32}{85} = 0.3765

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.3765 - 0.25}{\frac{\sqrt{0.25*0.75}}{\sqrt{85}}}

z = 2.69

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.3765, which is 1 subtracted by the p-value of z = 2.69.

Looking at the z-table, z = 2.69 has a p-value of 0.9964

1 - 0.9964 = 0.0036

The p-value of the test is 0.0036 < 0.05, thus we reject the null hypothesis that the proportion is 25%, and accept the alternate hypothesis that the proportion of schools needing such a waiver is above 25%.

6 0
3 years ago
Please help, it's urgent!
Aneli [31]

For this case we have to, by defining properties of powers and roots the following is fulfilled:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

We must rewrite the following expression:

\sqrt [3] {8 ^ {\frac {1} {4} x}}

Applying the property listed we have:

\sqrt [3] {8 ^ {\frac {1} {4} x}} = 8 ^ {\frac{\frac {1} {4} x} {3} }= 8 ^ {\frac {1} {4 * 3} x} = 8 ^ {\frac {1} {12} x}

Using the property again we have to:

8 ^ {\frac {1} {12} x} = \sqrt [12] {8 ^ x}

Thus, the correct option is option C

Answer:

Option C

6 0
4 years ago
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siniylev [52]
The answer is
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Decimal form:-1.94444444...
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