What equation is equivalent to -12+(-4/5)+31

Mathematics

1 answer:

s2008m [1.1K]3 years ago

8 0

Answer: -12 + (4/5) + 31 = 18.2

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What is the inverse of the function? f(x)=1/4x+10

egoroff_w [7]

Answer:

f^-1(x)=4x-40

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If f(x) = 7 + 4x and g(x)= 7x, what is the value of (f/g)(5)

andrew-mc [135]

The value of $(\frac{f}{g})(5)$ is $\frac{27}{35}$

Explanation:

Given that $f(x)=7+4x$ and $g(x)=7x$

The value of $(\frac{f}{g})(5)$ :

The value of $(\frac{f}{g})(5)$ can be determined by substituting x = 5 in the functions f(x) and g(x) and then dividing the terms, we get, the value of $(\frac{f}{g})(5)$

Thus, we have,

$(\frac{f}{g})(5)=\frac{f(5)}{g(5)}$

Substituting the value of x = 5 in the functions f(x) and g(x), we get,

$(\frac{f}{g})(5)=\frac{7+4(5)}{7(5)}$

Simplifying the terms, we have,

$(\frac{f}{g})(5)=\frac{7+20}{35}$

Adding the terms in numerator, we have,

$(\frac{f}{g})(5)=\frac{27}{35}$

Thus, the value of $(\frac{f}{g})(5)$ is $\frac{27}{35}$

8 0

3 years ago

Find the cube roots of 8(cos 216° + i sin 216°).

Tomtit [17]

$z^3=8(\cos216^\circ+i\sin216^\circ)$
$z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)$
$\implies z=8^{1/3}\left(\cos\left(\dfrac{216+360k}3\right)^\circ+i\sin\left(\dfrac{216+360k}3\right)^\circ\right)$

where $k=0,1,2$ . So the third roots are

$z=\begin{cases}2(\cos72^\circ+i\sin72^\circ)\\2(\cos192^\circ+i\sin192^\circ)\\2(\cos312^\circ+i\sin312^\circ)\end{cases}$