1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leva [86]
3 years ago
11

The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process. In the first step, manganese(I

I) carbonate and oxygen react to form manganese(IV) oxide and carbon dioxide:
2MnCOA9 + 02(g) 2 MnO2(s) + 2 CO2(g)
In the second step, manganese(IV) oxide and aluminum react to form manganese and aluminum oxidide
3Mn02(6)+4Als)3Mnsl20s)
Suppose the yield of the first step is 66% and the yield of the second step is 97'%. Calculate the mass of manganese(II) carbonate required to make 4.0 kg of manganese.
Be sure your answer has a unit symbol, if needed, and is rounded to the correct number of significant digits.
Chemistry
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

The answer is "6.52 kg and 13.1 kg"

Explanation:

For point a:  

Actual\ yield = 6.52 \ kg\\\\Percent \ yield= 66\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical\ yield} \times 100 \%\\\\Theoretical\ yield \ of \ MnO_2 = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\=\frac{6.52 \ kg}{66 \%} \times 100\% =9.88 \ kg\\\\

Equation:  

3MnCO_3 +O_2 \longrightarrow 2MnO_2 + 2CO_2\\\\

Calculating the amount of MnCO_3

= 9.88 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ MnO_2}{86.94 \ g} \times \frac{2 \ Mol \ MnCO_3}{2 \ mol \ MnO_2} \times \frac{114.95\ g}{1 \ mol \ MnCO_3 }\times \frac{1\ kg}{1000\ g}\\\\=  13.1 \ kg

For point b:

Actual\ yield = 4.0 \ kg\\\\Percent\ yield=97.0\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical \ yield} \times 100 \% \\\\Theoretical \ yield\  of\  Mn = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\

=\frac{4.0 \ kg}{97.0\%} \times 100\% =4.12 \ kg

Equation:  

3MnO_2 +4AL \longrightarrow 3Mn + 2AL_2O_3\\\\

Calculating the amount of MnO_2:  

= 4.12 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ Mn}{54.94 \ g} \times \frac{3 \ Mol \ MnO_2}{3 \ mol \ Mn} \times \frac{86.94 \ g}{1 \ mol \ MnO_2 }\\\\=  6516 \ g \\\\=6.52 \ kg\\\\

You might be interested in
Consider a 1260-kg automobile clocked by law-enforcement radar at a speed of 85.5 km/h. If the position of the car is known to w
-BARSIC- [3]
The expected speed is v = 85.5 km/h
 v = 85.5 km/h = (85.5 km/h)*(0.2778 (m/s)/(km/h)) = 23.75 m/s

If there is an uncertainty of 2 meters in measuring the position, then within a 1-second time interval:
The lower measurement for the speed is v₁ = 21.75 m/s,
The upper measurement for the speed is v₂ = 25.75 m/s.
The range of variation is
Δv = v₂ - v₁ = 4 m/s

The uncertainty in measuring the speed is
Δv/v = 4/23.75 = 0.1684 = 16.84%

Answer: 16.8%
3 0
3 years ago
Consider the reaction of A(g) + B(g) + C(g) => D(g) for whichthe following data were obtained:
AveGali [126]

Answer:

rate= k[A]²[B]²[C]

Explanation:

When concentration of A is increased two times ,keeping other's concentration constant , rate of reaction becomes 4 times .

So rate is proportional to [A]²

When concentration of B is increased two times , keeping other's concentration constant,rate of reaction becomes 4 times.

So rate is proportional to [B]²

When concentration of C is increased two times , keeping other's concentration constant, rate of reaction becomes 2 times.

So rate is proportional to [C]

So rate= k[A]²[B]²[C]

5 0
3 years ago
the area that stretches from the highest high-tide line on land out to he point of the continental shelf exposed by he lowest lo
allsm [11]
Is called the Intertidal zone

4 0
3 years ago
Which change in this process would shift the equilibrium to produce the
vampirchik [111]

Answer: B I think, I'll put my reasoning below.

Explanation:

It's not A because removing N2 would only shift the equation the opposite way.

It's not C and D because I don't think those affect the specific amount of each reactant/product produced. I think temperature only affects the speed at which the reaction is performed, which won't affect anything in this case.

7 0
2 years ago
Read 2 more answers
Which of the following statement(s) is/are consistent with the Bohr theory of the atom (and no other)?
olganol [36]

Answer:

(2) The lowest energy orbits are those closest to the nucleus.  

Explanation:

In the Bohr theory  the electrons describe circular orbits around the nucleus of the atom without radiating energy, therefore to maintain the circular orbit, the force that the electron experiences, that is, the coulombian force due to the presence of the nucleus, must be equal to the centripetal force.

The electron only emits or absorbs energy in the jumps from one allowed orbit to another, with only one jump occurring at a time, from layer K (n = 1) to layer L (n = 2),  without going through intermediate orbits. In said change it emits or absorbs a photon whose energy is the difference in energy between both levels.

In Bohr's model, it is stipulated that the energy of the electron is greater the greater the radius r, so the lowest energy orbits are those closest to the nucleus.

5 0
3 years ago
Other questions:
  • What properties are attributed to a solid with the type of bonding represented in the picture?
    7·1 answer
  • If the density of an object is 5.2g/cm3, and it’s volume is 3.7 cm3, what is it’s mass?
    8·1 answer
  • Gravity is a force of attraction between two or more masses. The gravitational attraction between the Sun and each of the planet
    12·1 answer
  • How many grams of carbon dioxide would be formed if 38.9 g C2H2 reacted completely with oxygen
    8·2 answers
  • What is the concentration of a HF solution with a PH of 2.3
    8·1 answer
  • I need help plssss asap
    11·2 answers
  • Can u please answer this for me
    14·1 answer
  • Write one word for the following short form of an element​
    15·1 answer
  • What is the electron configuration of the element in group 14 and period 4 of the periodic table
    15·1 answer
  • Look at the reaction below. upper h subscript 2 upper s upper o subscript 4 (a q) plus upper c a (upper o upper h) subscript 2 (
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!