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timofeeve [1]
3 years ago
15

There are ________ unpaired electrons in the Lewis symbol for a nitride ion.

Chemistry
1 answer:
Anna71 [15]3 years ago
5 0

Answer:

There are no unpaired electrons.

Explanation:

There are  no unpaired electrons in the Lewis symbol for a nitride ion({ N }^{ 3- }).The nitride ion has a charge of -3. The negative charge on the Nitride ion indicates a gain in electrons . Nitrogen has 5 valence electrons that is the number of electrons that are in its outer shell .The total number of electrons that the nitride ion has is equal to 5+3 = 8 electrons . Electrons usually appear in pairs and obey the octet rule therefore the nitride ion has four electron pairs no unpaired electrons.

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Which side of the electromagnetic spectrum has shorter wavelengths
kondaur [170]

Answer:blue blue blue

Explanation:

Just answered it and got it right

7 0
3 years ago
Read 2 more answers
Susie cooked sausages on a barbecue. Fat and water in the sausages changed state. which two changes of state occur during this p
padilas [110]

Answer:

The options a and b are correct

Explanation:

This options provided to the question are the answers to the question. But for clarification. When the fat melts, the change of state that occurs here is from solid to liquid (which is called melting) while the change of state that occurs when the water evaporated is from liquid to gas (which is called evaporation).

5 0
3 years ago
How many grams of Al(no2)3 should be added to 1.3L of water to prepare a 2.0M solution
Virty [35]

Answer: 429 grams of Al(NO_2)_3  should be added to 1.3 L of water to prepare 2.0 M solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute Al(NO_2)_3 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{165g/mol} 

V_s = volume of solution in Liters  

Now put all the given values in the formula of molarity, we get

2.0M=\frac{xg}{165g/mol\times 1.3L}

x=429g

Therefore, 429 grams of Al(NO_2)_3  should be added to 1.3 L of water to prepare 2.0 M solution

3 0
3 years ago
The concentration of ag+ in a solution saturated with ag2c2o4(s) is 1.7 × 10-4 m. calculate ksp for ag2c2o4.
Gelneren [198K]
<span>Silver oxalate dissociation equation is following: 
</span><span>
Ag</span>₂C₂O₄(s) ⇄ 2Ag⁺(aq) + C₂O₄²⁻(aq)

According to reaction follows next stoichiometric ratio:

[Ag⁺] : [C₂O₄²⁻] = 2 : 1

[C₂O₄²⁻] = [Ag⁺] / 2

[C₂O₄²⁻] = (1.7×10⁻⁴)/2 = 8.5×10⁻⁵ M

So, solubility product constants for silver oxalate is:

Ksp = [Ag⁺]² x [C₂O₄²⁻]

Ksp = [1.7×10⁻⁴]² x [8.5×10⁻⁵]

Ksp = 2.46×10⁻¹²



4 0
3 years ago
Nail polish remover containing acetone was spilled in a room 7.2 m × 5.8 m × 3.9 m. Measurements indicated that 6,400 mg of acet
sergeinik [125]

Volume of room  = 7.2 m \times 5.8 m \times  3.9 m

= 162.864 m^{3}

Now, according to conversion factor, convert 6,400 mg to micrograms

Since, 1 mg is equal to 1000 microgram.

Therefore, 6,400 mg  = 6,400 \times 1000

= 6,400,000 micrograms of acetone.

To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.

Thus,

Concentration of acetone  = \frac{6,400,000 microgram}{162.864 m^{3}}

= 39296.5910 microgram per cubic meter or 3.92\times 10^{4} \mu g/m^{3}\simeq 4.0\times 10^{4} \mu g/m^{3}

Hence, concentration of acetone is equal to 4.0\times 10^{4} \mu g/m^{3}

7 0
3 years ago
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