If −6n=−48<br> then n=<br> HELP PLEASE

algol13

The answer is negative 80 or like this -80

6 0

3 years ago

Represent <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%207%7D%7B5%7D%20" id="TexFormula1" title=" \frac{ - 7}{5} " al

Ilya [14]

Given:

The number is $-\dfrac{7}{5}$ .

To find:

The location of the given number of the number line.

Solution:

We have,

$Number=-\dfrac{7}{5}$

It can be written as

$Number=-\dfrac{5+2}{5}$

$Number=-\dfrac{5}{5}-\dfrac{2}{5}$

$Number=-1-\dfrac{2}{5}$

It means the number is less than -1 but more than -2. So, the number lies between -2 and -1.

The mixed fraction form of given number is

$Number=-(1+\dfrac{2}{5})$

$Number=-(1\dfrac{2}{5})$

$Number=-1\dfrac{2}{5}$

Divide the number in 5 equal parts between two consecutive integers.

Now each unit represents $\dfrac{1}{5}$ .

Since $Number=-1-\dfrac{2}{5}$ , therefore, it is 2 units left from -1.

The number line is given below.

3 0

3 years ago

Which of the following sums would be under the radical symbol to find the distance between the points (7, -1) and (-8, -9)?

Alexxandr [17]

Sadly, you didn't put any sums on your list of choices.
In fact, I can't even find a list of choices !

To find the distance between (7, -1) and (-8, -9),
you would build a sum under a square-root (radical)
symbol, and it would look something like this:

√ ( 225 + 64 ) .

5 0

3 years ago

Read 2 more answers

If you were to roll two dice, how many different ways could you roll double fours?

muminat

Answer:

There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice. So you have a 16.7% probability of rolling doubles with 2 fair six-sided dice

Step-by-step explanation:

5 0

3 years ago

. Ravi plays a game in which he has to draw one ball from a box containing 3 Red, 4 white and 3 green balls. On drawing a white

Slav-nsk [51]

P(Ravi is rewarded Rs. 10) = 0.4

P(Ravi does not lose) = 0.7

P(Ravi pays a penalty) = 0.3

Step-by-step explanation:

Step 1 :

Probability of any event happening = Total number of favorable outcomes / Total number of outcomes

Step 2 :

(i) P (Ravi is rewarded Rs. 10) = P(Ravi selecting a white ball)

Total number of favorable outcomes = Total number of white balls = 4

Total number number of outcomes = 10

Probability of selecting a white ball = Total number of white balls/Total number of outcomes =4/10 = 0.4

Hence P (Ravi is rewarded Rs. 10) = 0.4

Step 3 :

(ii) P (Ravi does not lose)

Probability of Ravi not losing is probability of Ravi not selecting a Red ball [ because Ravi has to pay penalty only when he chooses red ball

P(Ravi selecting Red ball) = Total number of red balls/Total number of outcomes =3/10 = 0.3

Hence P (Ravi does not lose) = 1-0.3 = 0.7

Step 3 :

(iii)P (Ravi pays a penalty of Rs. 5)

P (Ravi pays a penalty of Rs. 5)= Ravi selecting a Red ball

P(Ravi selecting Red ball) = Total number of red balls/Total number of outcomes =3/10 = 0.3

Hence P (Ravi pays a penalty of Rs. 5) = 0.3

5 0

3 years ago

If −6n=−48 then n= HELP PLEASE