If −6n=−48<br> then n=<br> HELP PLEASE

Describe and correct the error : |-13| - |13| = -13 - 13 = 26

hjlf

First,
|-13| represents the absolute value of the number 13. Absolute values cannot be negative. So |-13| cannot become -13, it would become 13.

So,
|-13| - |13| = -13 - 13 = 26 would become
|-13| - |13| = 13 - 13 = 0

8 0

4 years ago

You are on a basketball team and you score 84 points in 6 games

PilotLPTM [1.2K]

Answer:

14

Step-by-step explanation:

Think how many times does 6 go into 84.

you can divide 84 into 6 which is 14.

Or you can think what times 6 equals 84.

5 0

3 years ago

Read 2 more answers

Chris sold 5.5 pounds of trail mix. He sold it for $3.98 per pound. How much money did he collect?

Eva8 [605]

Answer:

7.28

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The amount of coffee that a filling machine puts into an 8-ounce jar is normally distributed with a mean of 8.2 ounces and a sta

nordsb [41]

Answer:

73.30% probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 8.2, \sigma = 0.18, n = 100, s = \frac{0.18}{\sqrt{100}} = 0.018$

What is the probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce?

This is the pvalue of Z when X = 8.2 + 0.02 = 8.22 subtracted by the pvalue of Z when X = 8.2 - 0.02 = 8.18. So

X = 8.22

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.22 - 8.2}{0.018}$

$Z = 1.11$

$Z = 1.11$ has a pvalue of 0.8665

X = 8.18

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.18 - 8.2}{0.018}$

$Z = -1.11$

$Z = -1.11$ has a pvalue of 0.1335

0.8665 - 0.1335 = 0.7330

73.30% probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce

8 0

4 years ago

The value

ehidna [41]

Answer:

A

Step-by-step explanation:

Check the solution by substituting x = $\frac{\pi }{2}$ into the left side of the equation

2sin²x - sinx - 1

= 2sin²( $\frac{\pi }{2}$ ) - sin ( $\frac{\pi }{2}$ ) - 1

= 2(1)² - 1 - 1

= 2 - 1 - 1

= 0

= right side

$\frac{\pi }{2}$ is therefore a solution to the equation

7 0

3 years ago

If −6n=−48 then n= HELP PLEASE