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Masteriza [31]
3 years ago
14

If −6n=−48 then n= HELP PLEASE

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

8

Step-by-step explanation:

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Solve for x. x2 + 7x + 10 = 0
algol13
The answer is negative 80 or like this -80
6 0
3 years ago
Represent <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%207%7D%7B5%7D%20" id="TexFormula1" title=" \frac{ - 7}{5} " al
Ilya [14]

Given:

The number is -\dfrac{7}{5}.

To find:

The location of the given number of the number line.

Solution:

We have,

Number=-\dfrac{7}{5}

It can be written as

Number=-\dfrac{5+2}{5}

Number=-\dfrac{5}{5}-\dfrac{2}{5}

Number=-1-\dfrac{2}{5}

It means the number is less than -1 but more than -2. So, the number lies between -2 and -1.

The mixed fraction form of given number is

Number=-(1+\dfrac{2}{5})

Number=-(1\dfrac{2}{5})

Number=-1\dfrac{2}{5}

Divide the number in 5 equal parts between two consecutive integers.

Now each unit represents \dfrac{1}{5}.

Since Number=-1-\dfrac{2}{5}, therefore, it is 2 units left from -1.

The number line is given below.

3 0
3 years ago
Which of the following sums would be under the radical symbol to find the distance between the points (7, -1) and (-8, -9)?
Alexxandr [17]

Sadly, you didn't put any sums on your list of choices. 
In fact, I can't even find a list of choices !

To find the distance between  (7, -1)  and  (-8, -9),
you would build a sum under a square-root (radical)
symbol, and it would look something like this:

               √ ( 225 + 64 ) .
 
5 0
3 years ago
Read 2 more answers
If you were to roll two dice, how many different ways could you roll double fours?
muminat

Answer:

There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice. So you have a 16.7% probability of rolling doubles with 2 fair six-sided dice

Step-by-step explanation:

5 0
3 years ago
. ​Ravi plays a game in which he has to draw one ball from a box containing 3 Red, 4 white and 3 green balls. On drawing a white
Slav-nsk [51]

P(Ravi is rewarded Rs. 10) = 0.4

P(Ravi does not lose) = 0.7

P(Ravi pays a penalty) = 0.3

Step-by-step explanation:

Step 1 :

Probability of any event happening  = Total number of favorable outcomes / Total number of outcomes

Step 2 :

(i)  P (Ravi is rewarded Rs. 10) = P(Ravi selecting a white ball)

Total number of favorable outcomes = Total number of white balls = 4

Total number number of outcomes = 10

Probability of selecting a white ball = Total number of white balls/Total number of outcomes =4/10 = 0.4

Hence  P (Ravi is rewarded Rs. 10) = 0.4

Step 3 :

(ii)  P (Ravi does not lose)

Probability of Ravi not losing is probability of Ravi not selecting a Red ball [ because Ravi has to pay penalty only when he chooses red ball

P(Ravi selecting  Red ball) = Total number of red balls/Total number of outcomes =3/10 = 0.3

Hence P (Ravi does not lose)  = 1-0.3 = 0.7

Step 3 :

(iii)P (Ravi pays a penalty of Rs. 5)

P (Ravi pays a penalty of Rs. 5)=  Ravi selecting a Red ball

P(Ravi selecting  Red ball) = Total number of red balls/Total number of outcomes =3/10 = 0.3

Hence P (Ravi pays a penalty of Rs. 5) = 0.3

5 0
3 years ago
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