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jonny [76]
3 years ago
6

HELP PLEASE!! I WILL TRY AND GIVE BRAINLEIST TO THE MOST DETAILED ANSWER ON BOTH.

Mathematics
1 answer:
Mila [183]3 years ago
6 0
Answer: 46x3
I hope this helped! :)
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The scale model of a skyscraper being built is 4.2 feet tall.
BigorU [14]
A. Convert 4.2 feet to meters. 4.2 feet = 1.28016 meters. The Formula of Scale  = Big / Small
Scale = 525 meters / 1.28016 meters
Scale = 410.1050 meters

b. Convert 4.2 feet to inches. 4.2 feet = 50.4 inches.
To get the number of plywood, divide 50.4 inches by 0.6 inch. The answer is 84. So there are 84 plywood sheets.
7 0
3 years ago
Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant
pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)

Applying the following property of exponentials numbers in (II):

e^{a}.e^{b}=e^{a+b}

Therefore e^{-28k} can be written as e^{-14k}.e^{-14k}

152=190-Ae^{-14k}.e^{14k}

Replacing (I) in the previous equation:

152=190-76e^{-14k}

Solving for k:

Subtracting 190 both sides, dividing by -76:

0.5=e^{-14k}

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76

Dividing by 0.5

A=152

7 0
3 years ago
2x −3 y = 21 hmu wit da answer
bazaltina [42]

slope is 2/3 and y intercept is 7

5 0
3 years ago
What is 1/6 plus 3/6 as a decimal?
Digiron [165]
1/6 + 3/6 = 4/6
               = 2/3
               = 0.6 recurring
               = 0.6666666667 
4 0
3 years ago
Part B
Troyanec [42]

Answer:

Part A) The length of a straight line between the school and the Fire Station is 4.6\ miles

Part B) The length of a straight line between the school and the hospital is 2.1\ miles

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

so

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

so

The coordinates of Fire Station are C(4.3,1.7)

What is the length of a straight line between the school and the Fire Station?

Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and C(4.3,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}

d=\sqrt{(1.7)^{2}+(4.3)^{2}}

d=4.6\ miles

Part B) we have that

The hospital is 3.1 miles west of the fire station

so

The coordinates of the hospital are D(4.3-3.1,1.7)

D(1.2,1.7)

What is the length of a straight line between the school and the hospital?

Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and D(1.2,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}

d=\sqrt{(1.7)^{2}+(1.2)^{2}}

d=2.1\ miles

7 0
3 years ago
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