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e-lub [12.9K]
3 years ago
5

g In transcription, the 3'-hydroxyl group of the growing RNA strand: Group of answer choices NONE OF THESE binds to the 5' ribos

e. attacks the outermost phosphorous group of the incoming nucleotide. ALL OF THESE attacks the 5' hydrogen of the incoming nucleotide. interacts with a positively charged metal ion in the active site.
Biology
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

attacks the outermost phosphorous group of the incoming nucleotide.  

Explanation:

Transcription is the biological process where RNA is formed. As you may already know, RNA is an extremely important nucleic acid for genetic processes and the production of proteins. The transcription has three steps that are called start, elongation and end. In the elongation phase, the RNA strand is growing, at this time, RNA polymerase, which is the enzyme responsible for RNA elaboration, places the nucleotides, in the RNA strand, in the 5' - 3' direction. This enzyme causes the hydroxyl, which makes up the nucleotide at the 3' end of the forming RNA, to attack the phosphorus present in the incoming  ribonucleotide.

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6 0
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in glucose the anomeric carbon is the first carbon, whereas in fructose, the anomeric carbon is the second carbon. The anomeric carbon is the one containing the carbonyl group (carbonyl group is a functional group composed of a carbon atom double-bonded to an oxygen atom: C=O)

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