<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
Answer:
Acute angle = 30°
Obtuse angle = 150°
Step-by-step explanation:
Method 1:
Let x represent the measurement of the obtuse angle
Obtuse angle = x
Acute angle = ⅕ of x = x/5
Thus:
x + x/5 = 180° (angels on a straight line)
Solve for x
(5x + x)/5 = 180
Multiply both sides by 5
5x + x = 180 × 5
6x = 900
x = 900/6
x = 150
Obtuse angle = 150°
Acute angle = x/5 = 150/5 = 30°
Method 2:
Since acute angle = ⅕ of the obtuse angle, therefore,
Obtuse angle = 5*acute angle
Let acute angle = x
Obtuse angle = 5x
Equation:
5x + x = 180° (angles on a straight line)
Solve for x
6x = 180
x = 180/6
x = 30
Acute angle = x = 30°
Obtuse angle = 5x = 5*30 = 150°
Answer: what
Step-by-step explanation:
No. you need to multiply both sides by 11 which would make it -88 > t. 99 is not less than -88
