a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
To find out is 3/20 is larger than 2 we will convert 3/20 to a decimal. Lets do it:-
3/20
3 ÷ 20 = 0.15
Is 0.15 larger than 2?
No, 0.15 is not larger than 2.
So, 3/20 isn't larger than 2.
Hope I helped ya!! xD
16500 grams cuz i just used google lol
Answer:
Your answer would be
2(13+9x)
Step-by-step explanation:
Answer:
x=82
Step-by-step explanation: