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kherson [118]
3 years ago
6

Out of the answers 6 -1 13 and 5 which is the answer for 1 + -5

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
8 0
I don’t understand the first part but 1+-5= -4
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A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
3 years ago
SIMPLE HELP HELP HELP PLEASE ONLY 1 ANSWER NONE OF THE ABOVE OR ALL IS NOT THE ANSWER SO PLEASE DO IT RIGHT THIS TIME WILL GIVE
Eva8 [605]

Answer:

A

The first option is the correct!

They are parallel so they never connect! :)

Photos attached!

Hope this helps! Have a great day! :)

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3 years ago
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5.3 or 5.30 it doesn't matter how many 0's you add
5 0
3 years ago
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Mitchell took a math exam today. If he got 63 out of 84 questions correct, what percentage did Mitchell get wrong? (answer using
Mars2501 [29]

Answer:

75%


Step-by-step explanation:

If Mitchell took a math exam and got 63 out of 84 questions correct, that would turn into the fraction: 63/84

In order to convert this to a decimal, you divide 84 by 63 (since every fraction is a division problem), and get 0.75.

When you change decimals into percents, you move the decimal point two times to the right. So, that would be 75.

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I hope that helped :)

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Pani-rosa [81]
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