Answer:
Step-by-step explanation:
you mean u=ln x,v=ln y
ln(x^3y^2)=lnx^3+ln y^2
=3 ln x+2 ln y
=3u+2v
Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
Answer:
-3x and -6x
Step-by-step explanation:
Take a look at the missing spaces. Multiply -6 with x which equals -6x
Multiply -3 with x which equals -3x
Therefore, the answer is B, -3x and -6x
To get 4% of 800 you times 800 by 4 and divide it by 100. Once you have that amount you add it to 800 to find the amount you will have in your bank the first year.
To get the next year's amount you then get 4% of 832(because after the first year you have more than $800) and then add the 4% to 832, that is the answer for the second year.
To find the third year's amount you get 4% of the new amount (last year's total) and add it to last year's total, that is your total for the third year.
So the first year will be:
(800x4÷100)+800
=32+800
=832
The second year will be:
832+(832x4÷100)
=832+33.28
=865.28
The third year will be:
(865.28×4÷100)+865.28
=34.61(rounded off)+865.28
=899.89
