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Mrac [35]
3 years ago
7

5 pen cost 20. find the cost of 8 pens and then 15 pens​

Mathematics
1 answer:
Anna007 [38]3 years ago
3 0

Answer:

8 pen : 26

15 pen : 60

Step-by-step explanation:

5 pen = 20

Times both sides by 2

10 pen = 40

add 5 pen = 20

15 pen = 60

Divide 10 by 5

2 pen = 4

1 pen = 2

Add them together

3 pen = 6

Add 5 pens and 20

8 pen = 26

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Answer:

part 1) 0.78 seconds

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Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

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t ---> the time in seconds

we have

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This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

so

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Find the vertex

Convert the equation in vertex form

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h(t)=-16(t^{2}-\frac{25}{16}t)+5

Complete the square

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}

Rewrite as perfect squares

h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

The vertex is the point (\frac{25}{32},\frac{945}{64})

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

16(t-\frac{25}{32})^{2}=\frac{945}{64}

(t-\frac{25}{32})^{2}=\frac{945}{1,024}

square root both sides

(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}

t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}

the positive value is

t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec

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