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vovikov84 [41]
2 years ago
9

The store Matilda works at bought a pair of leggings for $12. They plan on selling them for $20. What percent are the leggings m

arked up?
Mathematics
1 answer:
Alexeev081 [22]2 years ago
6 0

Answer:

67%

Step-by-step explanation:

difference between the numbers = $8

8 ÷ 12 X 100 = 67%

You might be interested in
17.253 to the nearest tenth
Vlad1618 [11]

Answer:

17.3

Step-by-step explanation:

tens  ones. tenths hundredths thousandths

1        7       .   2          5                    3

We are rounding to the nearest tenth

We are rounding the 2 so we look at the 5.  If it is 5 or above we round up.

Since it is, we will round the 2 to a 3

17.3

7 0
2 years ago
Read 2 more answers
I need sum help please and thanks :)
Leona [35]

Answer:

6/16n is your answer I think

4 0
3 years ago
Carmen is mailing packages. Each small package costs her $2.60 to send. Each large package costs her $3.40. How much will it cos
Fantom [35]

Answer:

By themselves $18.20, $13.60, and together $31.80

Step-by-step explanation:

$2.60 multiplied by 7 equals $18.20

$3.40 multiplied by 4 equals $13.60

Together this equals $31.80

6 0
2 years ago
Please help me find the area of the shaded part
AURORKA [14]
First you have Define the area of the total shape. Next you'd have to find the area of the unshaded shapes. then you would multiply in that area by floor because there for unshaded boxes. finally you subtract each box from the total area to get an answer of 3x - 4
6 0
3 years ago
Check answer please
Cerrena [4.2K]
The fourth or the D) Option is correct.

To find the new induced matrix via a scalar quantified multiplication we have to multiply the scalar quantity with each element surrounded and provided in a composed (In this case) 3×3 or three times three matrix comprising 3 columns and 3 rows for each element which is having a valued numerical in each and every position.

Multiply the scalar quantity with each element with respect to its row and column positioning that is,

Row × Column. So;

(1 × 1) × 7, (2 × 1) × 7, (3 × 1) × 7, (1 × 2) × 7, (2 × 2) × 7, (3 × 2) × 7, (1 × 3) × 7, (2 × 3) × 7 and (3 × 3) × 7. This will provide the final answer, that is, the D) Option.

To interpret and make it more interesting in LaTeX form. Here is the solution with LaTeX induced matrix.

\mathcal{A = \begin{bmatrix}1 & 0 & 3 \\ 2 & -1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad 7A = 7 \times \begin{bmatrix}1 & 0 & 3 \\ 2 & - 1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}

\mathbf{\therefore \quad \begin{bmatrix}7 \times 1 & 7 \times 0 & 7 \times 3 \\ 7 \times 2 & 7 \times -1 & 7 \times 2 \\ 7 \times 0 & 7 \times 2 & 7 \times 1 \\ \end{bmatrix}}

\therefore \quad \begin{\bmatrix}7 & 14 & 0 \\ 0 & -7 & 14 \\ 21 & 14 & 7 \end{bmatrix}

Hope it helps.
5 0
3 years ago
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