The moles of oxygen produced is calculated as follows
write a balanced reacting equation, that is
Mg(ClO3)2 ---->MgCl2 + 3O2
from the equation above the reacting ratio of Mg(ClO3)2 to O2 is 1: 3 therefore the moles of O2 produced = 5.12 moles x3 =15.36 moles
<u>Given:</u>
Rate of appearance of O2 = 0.250 M/s
Time period = 5.50 s
<u>To determine:</u>
The concentration of O2 formed
<u>Explanation:</u>
2O3 (g) ↔ 3O2 (g)
Rate of appearance of O2 = 1/3 * Δ[O2]/Δt
Based on the given data:
0.250 M/s = 1/3 * [O2]/5.50 s
[O2 ] = 0.250 Ms⁻¹ * 3 * 5.50 s = 4.125 M
Ans: Amount of oxygen formed is 4.13 M
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