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fredd [130]
2 years ago
5

How do tidal bulges form?

Chemistry
1 answer:
Troyanec [42]2 years ago
4 0

Answer: The pull of the moon's gravity on Earth's water causes tidal bulges to form on the side closest to the moon and farthest from the moon. In the place where there are tidal bulges, high tide occurs along coastline.

Explanation:

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How many moles of CF4 can be produced when 8.95 mol C reacts with 7.88 mol F2?
Molodets [167]

The remaining moles of C is 5.01 moles while the remaining moles of F₂ is 0.

<h3>Reaction between Carbon and Fluorine </h3>

The reaction between carbon and Fluorine is given as;

C + 2F₂  -------> CF₄

1  :    2                1

from the reaction above,

2 moles of F₂ requires 1 mole of C

7.88 mole of  F₂ will require:    7.88/2 = 3.94 moles of C and 3.94 moles of CF₄.

The remaining moles of C = 8.95 - 3.94 = 5.01 moles while the remaining moles of F₂ is 0.

Learn more about moles here: brainly.com/question/15356425

#SPJ1

8 0
2 years ago
How do you know when a chemical equation is balanced?
kirza4 [7]

Both sides of the equation would be equal.

Hope This Helps You!

6 0
3 years ago
What elements comprise the largest portion of Earth's atmosphere?​
Mrrafil [7]

Answer:

Nitrogen and Oxygen make up 99% of the Earths atmosphere. Then Argon makes up the rest of the atmosphere.

3 0
3 years ago
Which of the following did your answer include?
IgorC [24]

Answer:

check all 4

Explanation:

3 0
3 years ago
You need to prepare 150 mL of 0.1 M solution of silver chloride. How much silver chloride is required?
Rudiy27

Answer:

amount of silver chloride required is 0.015 moles or 2.1504 g

Explanation:

0.1M AgCL means 0.1mol/dm³ or 0.1mol/L

1L = 1000mL

if 0.1mol of AgCl is contained in 1000mL of solution

then x will be contained in 150mL of solution

cross multiply to find x

x = (0.1*150)/1000

x= 0.015 moles

moles of silver chloride present in 150 mL of solution is 0.15 moles

To convert this to grams, simply multiply this value by the molar mass of silver chloride

molar mass of silver chloride AgCl =107.86 + 35.5

                                                     =143.36 g/mol

mass of AgCl = moles *molar mass

                       =0.015*143.36

                        =2.1504g

                        =

4 0
3 years ago
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