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zaharov [31]
3 years ago
11

10.0 mL of 0.0400 M KBrO3 and 10.0 mL 0.100 M HCl is mixed with 10.0 mL of 0.0100 M KI, 10.0 mL 0.00100 M Na2S2O3, 1.0 mL of sta

rch solution, and 10.0 mL H2. What is the concentration of H in this mixture expressed as molarity?
Chemistry
1 answer:
Oliga [24]3 years ago
5 0

Answer:

0.0196

Explanation:

The Total volume of the solution = Volume of (KBrO_3 + HCl + KI +Na_2S_2O_3 + Starch + H_2O)

= 10 mL + 10 mL + 10 mL+ 10 mL + 1 mL + 10 mL

= 51 mL

The concentration of  [H^+] = \dfrac{ mL \ used \times 0.1 \ M}{total \ volume}

= \dfrac{10 \ mL \times 0.1 M}{51 \ mL}

= 0.0196

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