Question

10.0 mL of 0.0400 M KBrO3 and 10.0 mL 0.100 M HCl is mixed with 10.0 mL of 0.0100 M KI, 10.0 mL 0.00100 M Na2S2O3, 1.0 mL of starch solution, and 10.0 mL H2. What is the concentration of H in this mixture expressed as molarity?

Answer 1

Answer:

0.0196

Explanation:

The Total volume of the solution = Volume of $(KBrO_3 + HCl + KI +Na_2S_2O_3 + Starch + H_2O)$

= 10 mL + 10 mL + 10 mL+ 10 mL + 1 mL + 10 mL

= 51 mL

The concentration of  $[H^+] = \dfrac{ mL \ used \times 0.1 \ M}{total \ volume}$

$= \dfrac{10 \ mL \times 0.1 M}{51 \ mL}$

= 0.0196