Explanation:
<h3><em>A chemical property is a characteristic of a particular substance that can be observed in a chemical </em><em>reaction</em></h3>
<em>. Some major chemical properties include flammability, toxicity, heat of combustion, pH value, rate of radioactive decay, and chemical stability.</em>
Answer:
required diameter is 7.65 mm
Explanation:
Given the data in the question;
F = 6660 N
l₀ = 380 mm = 0.38 m
E = 110 GPa = 110 × 10⁹ N/m²
Δl = 0.50 mm = 0.0005 m
So, lets assume the deformation is elastic;
d₀ = √( [4l₀F] / [πEΔl] )
we substitute
d₀ = √( [4 × 0.38 × 6660] / [π × (110 × 10⁹) × 0.0005]] )
d₀ = √( 10123.2 / 172787595.947 )
d₀ = √( 5.85875 × 10⁻⁵ )
d₀ = 0.007654 m
d₀ = ( 0.007654 × 1000 )mm
d₀ = 7.65 mm
Therefore, required diameter is 7.65 mm
Answer:
Mass of Cu(NO₃)₂ produced = 125.67 g
limiting reactant = Cu
Explanation:
Given data:
Mass of Cu = 42.6 g
Mass of HNO₃ = 84.0 g
What is limiting reactant = ?
Mass of Cu(NO₃)₂ produced = ?
Solution:
Chemical equation:
3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 4H₂O + 2NO
Number of moles of Cu:
Number of moles = mass/ molar mass
Number of moles = 42.6 g/63.546 g/mol
Number of moles = 0.67 mol
Number of moles of HNO₃:
Number of moles = mass/ molar mass
Number of moles = 84 g/63.01 g/mol
Number of moles = 1.3 mol
Now we will compare the moles of Cu(NO₃)₂ with HNO₃ and Cu from balance chemical equation.
HNO₃ : Cu(NO₃)₂
8 : 3
1.3 : 3/8×1.3 = 6
Cu : Cu(NO₃)₂
3 : 3
0.67 : 0.67
Number of moles of Cu(NO₃)₂ produced by Cu are less so Cu will limiting reactant.
Mass of Cu(NO₃)₂:
Mass = number of moles × molar mass
Mass = 0.67 mol × 187.56 g/mol
Mass = 125.67 g
Answer:
4
Explanation:
I dont know that's all you need