Answer:
4) 0.26 atm
Explanation:
In the process:
Benzene(l) → Benzene(g)
ΔG° for this process is:
ΔG° = -RT ln Q
<em>Where Q = P(Benzene(g)) / P°benzene(l) P° = 1atm</em>
ΔG° = 3700J/mol = -8.314J/molK * (60°C + 273.15) ln P(benzene) / 1atm
1.336 = ln P(benzene) / 1atm
0.26atm = P(benzene)
Right answer is:
<h3>4) 0.26 atm
</h3><h3 />
Answer:
12.77 M
Explanation:
8.3 moles of NaCl in .65 L of water ? Looking for M ?
8.3 M / .65 L = 12.77 M
H 3 0 + is hydronium ion. OH- is hydroxide ion. H+ is hydrogen ion
Answer:
The equilibrium position will shift towards the lefthand side.
Explanation:
[CoCl4] 2- (aq) + 6H2O (l) ⇌ [Co(H2O)6] 2+ (aq) + 4 Cl- (aq)
The equation written above in exothermic as written. That is, the forward reaction is exothermic. The equilibrium position is observable by monitoring the colour change of the solution. At the left hand side, the solution is blue but at the right hand side the solution is pink. Addition of heat (in a hot water bath) will shift the equilibrium towards the left hand side, that is formation of more [CoCl4] 2- making the solution to appear blue in colour.
Acetic acid is a weak acid. So, the undissociated acid molecules exist in equilibrium with the dissociated form. The equilibrium representing the weak acidic nature of acetic acid is,
The interior of the cell membrane is hydrophobic. So, the membrane allows uncharged species (hydrophobic) to pass through it. Charged groups cannot easily pass through the membrane. We can say acetic acid can easily pass through the membrane when compared to the charged form acetate ion. At low pH, more of the molecule will cross the membrane as most of the acetic acid will be in undissociated and uncharged form at a lower pH.
of acetic acid is around 4.8. So at a pH value less than 4.8, we can say the more of the acetic acid molecules can cross the membrane.
