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3 years ago

The Ka of carbonic acid is 4.3 x 10-7.

Chemistry

1 answer:

ratelena [41]3 years ago

3 0

Answer:

poor hydrogen-ion donor

Explanation:

Acid dissociation constant constant chemistry is the equilibrium constant of the dissociation reaction of an acid, it is denoted by Ka. This equilibrium constant is a measure of the strength of an acid in a solution.

Note these as a rule of thumb:

When Ka is large, the dissociation of the acid is favored.

When Ka is small, the acid does not dissociate to a large extent.

Hence, a Ka of 4.3 x 10-7 shows a weak acid. A weak acid is a poor hydrogen ion donor because it does not dissociate to a large extent in solution.

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What is the number of moles and the mass of Mg required to react with 7.50g of HCl and produce MgCl2 and H2? 1.25 g 2.50 g 5.00

boyakko [2]

Answer:

The correct option is: 2.50 g

Explanation:

Reaction involved: Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)

Molar mass: Mg = 24.305 g/mol, HCl = 36.461 g/mol

In the given reaction, 1 mole Mg reacts with 2 moles HCl.

Given: mass of HCl = 7.50 g

So, the number of moles of HCl = given mass ÷ molar mass = 7.50 g ÷ 36.461 g/mol = 0.2057 moles

Therefore, the<u> number of moles of Mg</u> that reacts with 0.2057 mole HCl = 0.2057 ÷ 2 = 0.1028 moles

Therefore, <u>the mass of Mg in grams</u> = molar mass × number of moles = 24.305 g/mol × 0.1028 mole = 2.5 g

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4 years ago

How many moles are in 3.0x10^24 molecules of water

Daniel [21]

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3 years ago

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A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.

julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

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