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3 years ago

The ksp of pbi2 is 1.4 x 10-8. what is the molar solubility of lead(ii iodide in a solution of 0.400 m sodium iodide?

1 answer:

8 0

The solubility product of a substance us calculated by the product of the concentration of the dissociated ions in the solution raise to the stoichiometric coefficient of the ions. Therefore, we need the dissociation reaction. For this, it will have the reaction:

PbI2 = Pb^2+ + 2I-

We solve as follows:

Ksp = [Pb2+][I-]^2 = 1.4 x 10-8
1.4 x 10-8 = x(2x)^2
1.4 x 10-8 = 4x^3
x = 1.5x10^-3 M

The molar solubility would be 1.5x10^-3 M.

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What stress would shift the equilibrium position of the following system to the left?

Margarita [4]

Answer:

Heating the system

Explanation:

According to the principle of Le Chatelier, for a system at equilibrium, a specific disturbance would make the equilibrium shift toward the direction which minimizes such a disturbance.

Since we wish to shift the equilibrium to the left, this means we wish to increase the concentration of products, as an excess in their concentration would make the products react and produce more reactants in order to lower the excess concentration of products.

Since heat is also a product, an increase in heat would shift the equilibrium toward the left, as this would consume the excess of heat by producing the reactants.

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3 years ago

If we react 30 grams of ethane (C2H6 ) with 320 grams of oxygen, how many grams of carbon dioxide would we make

V125BC [204]

The mass of carbon dioxide that would be made by reacting 30 grams C2H6 with 320 grams O2 will be 80 grams

From the balanced equation of the reaction:

$2C_2H_6+7O_2---4CO_2+6H_2O$

The mole ratio of C2H6 to O2 is 2:7.

Mole of 30 grams C2H6 = mass/molar mass

= 30/30

= 1 mole

Mole of 320 grams O2 = 320/32

= 10 moles

Thus, C2H6 is the limiting reactant.

Mole ratio of C2H6 to CO2 according to the equation = 1:2

Since the mole of C2H6 is 1, the equivalent mole of CO2 would, therefore, be 2.

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= 2 x 44

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More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults

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3 years ago

Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 8 moles of Al react with 8 moles of HBr, what is the limiting reactant?

TiliK225 [7]

Answer:- HBr is limiting reactant.

Solution:- The given balanced equation is:

$2Al+6HBr\rightarrow 2AlBr_3+3H_2$

From this equation, There is 2:6 mol or 1:3 mol ratio between Al and HBr. Since we have 8 moles of each, HBr is the limiting reactant as we need 3 moles of HBr for each mol of Al.

The calculations could be shown as:

$8molAl(\frac{6molHBr}{2molAl})$

= 24 mol HBr

From calculations, 24 moles of HBr are required to react completely with 8 moles of Al but only 8 moles of it are available. It clearly indicates, HBr is limiting reactant.

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3 years ago