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dsp73
2 years ago
10

There are a total of 71 students in the cafeteria.

Mathematics
1 answer:
Vsevolod [243]2 years ago
7 0

Answer:

49

Step-by-step explanation:

you can make the information into equations them solve simultaneously:

b + g = 71

b = 2g + 5

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Find a number lower than 19 that has more factors than 19,21,23, and 25
Len [333]
12 has more factors the 19,21,,23, and 25.
7 0
4 years ago
An organization has members who possess IQs in the top 4% of the population. If IQs are normally distributed, with a mean of 100
murzikaleks [220]

Answer:

The minimum IQ score will be "126".

Step-by-step explanation:

The given values are:

Mean

\mu = 100

Standard deviation

\sigma=15

Now,

⇒ P(z>x)=4 \ percent \ i.e., 0.04

⇒ P(z>\frac{x- \mu}{\sigma} )=0.04

⇒ 1-P(z \leq \frac{x-100}{15})=0.04

⇒ \frac{x-100}{15}=z0.96

            =NORMDIS(z=0.96)

            =1.751

⇒ x=100+15\times 1.751

      =126.265 \ i.e., 126

7 0
3 years ago
I need help with this please :)
Marina CMI [18]

9514 1404 393

Answer:

  all are Not Equivalent

Step-by-step explanation:

The coefficient of t³ in the target expression is -3. In order for that to be the result of simplifying any of the given expressions, they must have ( )^(t^3) in the denominator. None do, so none of the offered choices is equivalent to the given expression.

_____

The expressions simplify like this:

  \dfrac{(2^3)^{t^3}}{2^{5t}}=2^{3t^3-5t}\\\\\dfrac{8^{t^3}}{32^t}=2^{3t^3-5t}\\\\8^{t^3}\cdot32^t=2^{3t^3+5t}

4 0
3 years ago
Write 2.05 × 10^5 without exponents.
kondor19780726 [428]

Answer: 205000

Step-by-step explanation:

4 0
3 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
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