Answer:
16
1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168
No, because there are TWO values of y for a certain value of x
say x=5, then y=2 and y=-2
That does not satisfy the concept of the function.
The type of transformation that maps <span>∆ABC onto ∆A′B′C′ is a
reflection transformation
The triangle is reflected across the line y = 0.
</span><span>
When ∆A′B′C′ is reflected across the line x = -2 to form ∆A″B″C″,
B'' vertex
of ∆A″B″C″ will have the same coordinates as B′</span>
Answer:
given you are asked to simplify

Step-by-step explanation:
You have to multiply the numerator and denominator by the denominator's conjugate.
The conjugate of a+bi is a-bi.
When you multiply conjugates, you just have to multiply first and last.
(a+bi)(a-bi)
a^2-abi+abi-b^2i^2
a^2+0 -b^2(-1)
a^2+-b^2(-1)
a^2+b^2
See no need to use the whole foil method; the middle terms cancel.
So we are multiplying top and bottom of your fraction by (-3+4i):

So you will have to use the complete foil method for the numerator. Let's do that:
(-3+5i)(-3+4i)
First: (-3)(-3)=9
Outer:: (-3)(4i)=-12i
Inner: (5i)(-3)=-15i
Last: (5i)(4i)=20i^2=20(-1)=-20
--------------------------------------------Combine like terms:
9-20-12i-15i
Simplify:
-11-27i
Now the bottom (-3-4i)(-3+4i):
F(OI)L (we are skipping OI)
First:-3(-3)=9
Last: -4i(4i)=-16i^2=-16(-1)=16
---------------------------------------------Combine like terms:
9+16=25
So our answer is ![\frac{-11-27i}{25}{/tex] unless you want to seprate the fraction too:[tex]\frac{-11}{25}+\frac{-27}{25}i](https://tex.z-dn.net/?f=%5Cfrac%7B-11-27i%7D%7B25%7D%7B%2Ftex%5D%20unless%20you%20want%20to%20seprate%20the%20fraction%20too%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7B-11%7D%7B25%7D%2B%5Cfrac%7B-27%7D%7B25%7Di)