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3 years ago

Please solve this 6-3 log2n=0

Mathematics

2 answers:

viva [34]3 years ago

7 0

$6 - 3log2n = 0$

$-3log2n = -6$

$log2n = 2$

$10^{2} = 2n$

$100 = 2n$

$n = 50$

lutik1710 [3]3 years ago

6 0

If that is 6-3(log2n)=0 then how you would go about solving it is by looking at log2n like x. In this case, for 6-3x=0, x would have to =2. So log2n has to =2. If log2n=2 and we assume that the base is 10 (because if there is no written base on a log then it is 10) then we need to rewrite the log to exponential form. Rewritten it's 10^2=2n. 100=2n, divide both sides by 2 and you get n=50.

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2 years ago

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9514 1404 393

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a, c, b

Step-by-step explanation:

Collect terms, subtract the constant, divide by the y-coefficient.

(a) 4y + (y - 1) = 29 ⇒ y = 6

(b) 4y - y + 1 = 13 ⇒ y = 4 . . . . . this equation is not what you have written

<em>Additional comment</em>

The second equation suffers from a typo, so your answer may vary.

3 0

2 years ago

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In Image:

iris [78.8K]

Answer:

The answer to your question is x ≠ -10 x ≠ 2 x ≠ -2

Solution $\frac{(x- 8)(x + 2)}{(x + 8)(x - 2)}$

Step-by-step explanation:

Process

1.- Factor all the polynomials

$\frac{x^{2} -3x - 40}{x^{2} + 8x - 20} / \frac{x^{2}+ 13x + 40}{x^{2}+ 12x + 20}$ = $\frac{(x-8)(x + 5)}{(x + 10)(x- 2)} / \frac{(x+ 8)(x + 5)}{(x + 10)(x + 2)}$

2.- Invert the second term

= $\frac{(x- 8)(x + 5)}{(x +10)(x - 2)} \frac{(x+ 10)(x + 2)}{(x + 8)(x +5)}$

3.- Simplify

= $\frac{(x- 8)(x + 2)}{(x + 8)(x - 2)}$

4.- x must be different to

x ≠ -10 x ≠ 2 x ≠ -2

This values are from the factor expressions and then equal to zero.

8 0

2 years ago