Answer:
(x + 3)(x - 1)(x + 2)
Step-by-step explanation:
The fractions are:
![\dfrac{x + 2}{x^{2} + 2x - 3} \text{ and } \dfrac{x - 7}{x^{2} + 5x + 6}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%20%2B%202%7D%7Bx%5E%7B2%7D%20%2B%202x%20-%203%7D%20%5Ctext%7B%20and%20%7D%20%5Cdfrac%7Bx%20-%207%7D%7Bx%5E%7B2%7D%20%2B%205x%20%2B%206%7D)
Factor each denominator
![x^{2} + 2x - 3 = (x + 3)(x - 1)\\x^{2} + 5x + 6 = (x + 3)(x + 2)](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%202x%20-%203%20%3D%20%28x%20%2B%203%29%28x%20-%201%29%5C%5Cx%5E%7B2%7D%20%2B%205x%20%2B%206%20%3D%20%28x%20%2B%203%29%28x%20%2B%202%29)
We must find the least common multiple of the denominators. We take the maximum power of each separate factor.
Factors of first fraction = (x + 3) × (x - 1)
Factors of second fraction = (x + 3) × (x + 2)
LCM = (x + 3)(x - 1)(x + 2)
The lowest common denominator of the two fractions is (x + 3)(x - 1) (x + 2).
Answer:
3 lol
Step-by-step explanation:
Answer:
V220 should be the answer
Answer:
1) Function h
interval [3, 5]
rate of change 6
2) Function f
interval [3, 6]
rate of change 8.33
3) Function g
interval [2, 3]
rate of change 9.6
Step-by-step explanation:
we know that
To find the average rate of change, we divide the change in the output value by the change in the input value
the average rate of change is equal to
step 1
Find the average rate of change of function h(x) over interval [3,5]
Looking at the third picture (table)
Substitute
step 2
Find the average rate of change of function f(x) over interval [3,6]
Looking at the graph
Substitute
step 3
Find the average rate of change of function g(x) over interval [2,3]
we have
![g(x)=\frac{1}{5}(4)^x](https://tex.z-dn.net/?f=g%28x%29%3D%5Cfrac%7B1%7D%7B5%7D%284%29%5Ex)
Substitute
therefore
In order from least to greatest according to their average rates of change over those intervals
1) Function h
interval [3, 5]
rate of change 6
2) Function f
interval [3, 6]
rate of change 8.33
3) Function g
interval [2, 3]
rate of change 9.6
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