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irakobra [83]
3 years ago
12

What's the answer?to this show me the steps too because this is hard

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0
1.
w - the width
w + 6 - the length
40 - the area

Equation: w · (w + 6) = 40

w² + 6w = 40    |-40
w² + 6w - 40 = 0
w² + 10w - 4w - 40 = 0
w(w + 10) - 4(w + 10) = 0
(w + 10)(w - 4) = 0 ↔ w + 10 = 0 ∨ w - 4 = 0
w = -10 < 0; w = 4

The width is equal 4 ft.
The length is equal 4 + 6 = 10 ft.


2.
f(x - n) - right n units
f(x + n) - left n units
f(x) - n - down n units
f(x) + n - up n units

f(x) = x² - 3x - 4
f(x - 3) = (x- 3)² - 3(x-3) - 4

right 3 units.

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3 years ago
Can anyone help me find the (?,?) coordinates? The given shape is a parallelogram.
Sonja [21]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Given shape is a parallelogram.

Construction: Draw a line joining the diagonals.

<em>In parallelogram, diagonals bisect each other.</em>

Solve it using mid-point formula:

$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right  )

Here x_1=m, y_1=n, x_2=h, y_2=0

$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n+0}{2}\right  )

$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right  )

Using this midpoint find the missing coordinate.

$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right  )

Let the missing coordinates by x and y.

Here x_1=0, y_1=0, x_2=x,  y_2=y

$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{x}{2}, \frac{y}{2}\right  )

Now equate the x-coordinates and y-coordinates.

$ \frac{m+h}{2}=\frac{x}{2}, \  \  \  \frac{n}{2} =  \frac{y}{2}

Multiply by 2 on both sides of the equation, we get

m + h = x, n = y

x = m + h and y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

7 0
3 years ago
Answer please boys????
jasenka [17]
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d1i1m1o1n [39]
False because it just can not
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