What's the answer?to this show me the steps too because this is hard
1 answer:
1.
w - the width
w + 6 - the length
40 - the area
Equation: w · (w + 6) = 40
w² + 6w = 40 |-40
w² + 6w - 40 = 0
w² + 10w - 4w - 40 = 0
w(w + 10) - 4(w + 10) = 0
(w + 10)(w - 4) = 0 ↔ w + 10 = 0 ∨ w - 4 = 0
w = -10 < 0; w = 4
The width is equal 4 ft.
The length is equal 4 + 6 = 10 ft.
2.
f(x - n) - right n units
f(x + n) - left n units
f(x) - n - down n units
f(x) + n - up n units
f(x) = x² - 3x - 4
f(x - 3) = (x- 3)² - 3(x-3) - 4
right 3 units.
w - the width
w + 6 - the length
40 - the area
Equation: w · (w + 6) = 40
w² + 6w = 40 |-40
w² + 6w - 40 = 0
w² + 10w - 4w - 40 = 0
w(w + 10) - 4(w + 10) = 0
(w + 10)(w - 4) = 0 ↔ w + 10 = 0 ∨ w - 4 = 0
w = -10 < 0; w = 4
The width is equal 4 ft.
The length is equal 4 + 6 = 10 ft.
2.
f(x - n) - right n units
f(x + n) - left n units
f(x) - n - down n units
f(x) + n - up n units
f(x) = x² - 3x - 4
f(x - 3) = (x- 3)² - 3(x-3) - 4
right 3 units.
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Sketch the two quadrilaterals and label them as shown in the figure below.
Let x = length of the 4th side of ABCD.
Because ABCD ~ EFGH, therefore
x/5 = 14/6
That is,
x = (5/6)*14 = 11.67 ft
Answer: D. 11.7 ft
Let x = length of the 4th side of ABCD.
Because ABCD ~ EFGH, therefore
x/5 = 14/6
That is,
x = (5/6)*14 = 11.67 ft
Answer: D. 11.7 ft